6y + 4 I guess is the answer for the question
I believe that this is correct if anything is unclear/blurry just ask and i will tell u what i wrote
Answer:
4m
Step-by-step explanation:
Answer:
Step-by-step explanation:
The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.
To find the percentile for the television weights, use the formula:
, where is the average of the set, is some constant relevant to the percentile you're finding, and is one standard deviation.
As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute , , and :
Therefore, the 90th percentile weight is 5.1282 pounds.
Repeat the process for calculating the 10th percentile weight:
The difference between these two weights is .