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hodyreva [135]
3 years ago
13

The least common multiple of 20, 24, and 45 is _____. A. 30 B. 180 C. 360 D. 21,600

Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0

Answer:c because the least common multiple is 360

Step-by-step explanation:

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leonid [27]

Answer:

Jesse can pack 18 books.

Step-by-step explanation:

2.4*18=43.2+5.7==48.9

you cant fit more than fifty becaue 48.9+2.4=51.3, thus 18 is your answer

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3 years ago
What expression is equivalent to 12x^4/4x^16 helpppp
adoni [48]

Answer: 48x/64

Work (assuming ^ is multiplication):

12x^4/4x^16

12x ^ 4x = 48x

4 ^ 16 = 64

3 0
2 years ago
Select the correct answer from each drop-down menu.
yaroslaw [1]
The length of the bigger piece is 28 and the total length is 40
7 0
2 years ago
One-fifth the sum of one-half and one-third. WRITE IN A EXPRESSION FORM
vladimir2022 [97]

Answer:

1/6

Step-by-step explanation:

1/2 + 1/3 = 5/6

1/5 of 5/6 = 5/30

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8 0
3 years ago
What are the roots of the polynomial equation x^3-5x+5=2x^2-5? Use a graphing calculator and a system of equations. Round nonint
leonid [27]

The right answer is c. –2.24, 2, 2.24


This question needs to be solved in two ways. First, using a graphing calculator. Next, using a system of equations.


1. Using a graphing calculator.


We have the following polynomial equation:

x^3-5x+5=2x^2-5


By ordering this equation we have:

x^3-2x^2-5x+10=0


So, we can say that this equation comes from a function given by:

f(x)=x^3-2x^2-5x+10


Thus, by plotting this function, we have that the graph of this function is indicated in Figure 1. By zooming, we can see, in Figure 2, that the roots of the polynomial equation are the x-intercepts of f(x) which are:


x_{1}=-2.236 \\ \\ x_{2}=2 \\ \\ x_{3}=2.236


Finally, rounding noninteger roots to the nearest hundredth we have:


\boxed{Root_{1}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=2.24}


2. Using a system of equations.


The ordered equation is:

x^3-2x^2-5x+10=0


By arranging to factor out we have:

x^3-5x-2x^2+10=0


Then, by factoring:

x(x^2-5)-2(x^2-5)=0


Term (x^2-5) is a common factor, thus:


(x-2)(x^2-5)=0 \\ \\ (x-2)(x-\sqrt{5})(x+\sqrt{5})=0 \\ \\ Finally: \\ \\ \boxed{Root_{1}=-\sqrt{5}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=\sqrt{5}=2.24}

6 0
3 years ago
Read 2 more answers
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