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3 years ago

Help please give you 20 points

Mathematics

1 answer:

kicyunya [14]3 years ago

7 0

Answer:

Step-by-step explanation:

The x intercepts are the points on the graph that touch the x axis in this case the 1 and the 5 are spot on.

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Write 2.9302 as a fraction and a mixed number

bonufazy [111]

rationalise 29302/100000

=14651/50000

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2 years ago

Solve for t 1/2t + 6 = -7

zhuklara [117]

1/2t+6=-7
1/2t=-13
t=-26

7 0

3 years ago

Read 2 more answers

Please Help me!

hoa [83]

Answer:

domain (-4,infinity) range (negative infinity, infinity)

Step-by-step explanation:

The domain is the x axis. the x axis starts at -4 and keeps going meaning it goes to infinity. the range is the y axis. the range has no determined starting point or end point meaning it goes to negative infinity and positive infinity

8 0

3 years ago

Solve 5 tan x = 5√(3) for 0° ≤ x ≤ 180°. a. 60° b. 150° c. 30° d. 120°

ladessa [460]

Answer:

$\boxed{a.\:\:\:60\degree}$

Step-by-step explanation:

The given trigonometric equation is

$5\tan(x)=5\sqrt{3}$ for $0\degree \le x\le 180\degree$ .

We divide through by 5 to get;

$\tan(x)=\sqrt{3}$

We take the inverse tangent of both sides to obtain;

$x=tan^{-1}(\sqrt{3})$

$x=60\degree$

Since the tangent ratio is positive, it means $x$ could also be in the 3rd quadrant. But this is outside the given range.

Therefore the correct answer is A

6 0

3 years ago

Tan inverse X + tan inverse Y + tan inverse z=pie prove that X+Y+Z=xyz

vfiekz [6]

Answer:

see explanation

Step-by-step explanation:

Given

$tan^{-1}$ x + $tan^{-1}$ y + $tan^{-1}$ z = π

let

$tan^{-1}$ x = A , $tan^{-1}$ y = B , $tan^{-1}$ z = C , so

x = tanA, y = tanB , z = tanC

Substituting values

A + B + C = π ( subtract C from both sides )

A + B = π - C ( take tan of both sides )

tan(A + B) = tan(π - C) = - tanC ( expand left side using addition identity for tan )

$\frac{tanA+tanB}{1-tanAtanB}$ = - tanC ( multiply both sides by 1 - tanAtanB )

tanA + tanB = - tanC( 1 - tanAtanB) ← distribute

tanA+ tanB = - tanC + tanAtanBtanC ( add tanC to both sides )

tanA + tanB + tanC = tanAtanBtanC , that is

x + y + z = xyz

3 0

3 years ago