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anastassius [24]
3 years ago
8

Let R be the triangular region in the first quadrant with vertices at.Points (0,0), (h,0), and (h,r), where r and h are positive

constants
Mathematics
1 answer:
Romashka [77]3 years ago
3 0

Answer:

The answer is "\pi  \int^{h}_{0}(\frac{r}{h} x)^2 \ dx"

Step-by-step explanation:

dv=(Area) \ thickness

    =\pi r^2 \ dx\\\\=\pi (\frac{r}{h} x)^2 \ dx  

V= \int^{h}_{0} \pi (\frac{r}{h} x)^2 \ dx\\\\

   =\pi  \int^{h}_{0}(\frac{r}{h} x)^2 \ dx

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Jonathon buys 3 crates of flowers. He plants 2/5 pf the flowers and then divides the remaining flowers among 5 friends. What fra
GarryVolchara [31]

Answer:

2/5 of 3 = 2/5 * 3 = 6/5....what he plants

(6/5) / 5 = 6/5 * 1/5 = 6/25 <== what each friend got

Step-by-step explanation:

7 0
3 years ago
This problem has been solved!See the answerA municipal bond service has three rating categories (A, B, and C). Suppose that in t
mariarad [96]

Answer:

a. \frac{35}{51}

b. \frac{51}{100}

c. \frac{1}{5}

Step-by-step explanation:

Suppose cities represented by C', suburbs represented by S and rural represented by R,

Let x be the total number of bonds issued throughout the US,

According to the question,

n(A) = 70% of x = 0.7x,

n(B) = 10% of x = 0.1x,

n(C) = 20% of x = 0.2x,

n(A∩C') = 50% of n(A) = 0.5 × 0.7x = 0.35x,

n(A∩S) = 20% of n(A) = 0.2 × 0.7x = 0.14x,

n(A∩R) = 30% of n(A) = 0.3 × 0.7x = 0.21x,

n(B∩C') = 40% of n(B) = 0.4 × 0.1x = 0.04x,

n(B∩S) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(B∩R) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(C∩C') = 60% of n(C) = 0.6 × 0.2x = 0.12x,

n(C∩S) = 15% of n(C) = 0.15 × 0.2x = 0.03x,

n(C∩R) = 25% of n(C) = 0.25 × 0.2x = 0.05x,

n(C') = n(A∩C')  + n(B∩C')  + n(C∩C')  = 0.35x + 0.04x + 0.12x = 0.51x

n(S) = n(A∩S) + n(B∩S) + n(C∩S) = 0.14x + 0.03x + 0.03x = 0.20x

a. The probability that it will receive an A rating, if a new municipal bond is to be issued by a city,

P(\frac{A}{C'})=\frac{P(A\cap C')}{P(C')}=\frac{0.35x/x}{0.51x/x}=\frac{0.35}{0.51}=\frac{35}{51}

b. The proportion of municipal bonds are issued by cities = \frac{n(C')}{x}

=\frac{0.51x}{x}

=\frac{51}{100}

c. The proportion of municipal bonds are issued by suburbs = \frac{n(S)}{x}

=\frac{0.20x}{x}

=\frac{20}{100}

=\frac{1}{5}

3 0
2 years ago
Help!
TEA [102]
Multiply both sides by 10...
So u = 50/11 = 4.5454... = 4.55
5 0
3 years ago
What is the equation for the nth term of the arithmetic sequence.<br> 28, 25, 22, 19, ....
natka813 [3]

Answer:

31-3n

Step-by-step explanation:

d=-3

a1=28

an= 28+(n-1)(-3)=28-3n+3

an=31-3n

4 0
3 years ago
What is the 38th term of 459,450,441,..
galina1969 [7]

Answer:

The 38th term of 459,450,441,.. will be:

a_{13}=351

Step-by-step explanation:

Given the sequence

459,450,441,..

An arithmetic sequence has a constant difference 'd' and is defined by

a_n=a_1+\left(n-1\right)d

computing the differences of all the adjacent terms

450-459=-9,\:\quad \:441-450=-9

so

d=-9

The first element of the sequence is

a_1=459

so the nth term will be

a_n=-9\left(n-1\right)+459

a_n=-9n+468

Putting n=38 to find the 38th term

a_n=-9n+468

a_{13}=-9\left(13\right)+468

a_{13}=-117+468

a_{13}=351

Therefore, the 38th term of 459,450,441,.. will be:

a_{13}=351

3 0
3 years ago
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