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kykrilka [37]
3 years ago
14

What are the answers for these questions?

Mathematics
1 answer:
serg [7]3 years ago
8 0

Answer:

Explanation

Step-by-step explanation:

I got you bro.

#1 and #2 are the same. Basically domain is the x value. So when the ordered pair says something like (4,3) The X value is 4 otherwise known as the domain. The range is the second number like as 6 in (1,6). The range is otherwise known as the y values.

#3 and #4 are basically the same thing again. In the column with the X's are the domain and the y's are the range

#5 is fairly simple too. The left bubble with the numbers represent the domain (x values) and the right bubble with numbers represent the range (y values).

What you have to do is create ordered pairs by taking a number in the left bubble and match it with a number from the y side.

Answers: (-2,3) (-1,3) (1,0) (1,5) (-1,6) (4,5)

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FromTheMoon [43]

Answer:

its A

Step-by-step explanation:

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sertanlavr [38]

Answer:

13a² - 39a + 46

Step-by-step explanation:

To find g(a-2)+3g(2a), find each part using the function g(x)=x²-5x+8.

g(a-2) = (a-2)²-5(a-2)+8 = a² - 4a + 4-5a + 10+8 = a² - 9a + 22

3g(2a) = 3{(2a)²-5(2a)+8} = 3{ 4a² - 10a + 8} = 12a² - 30a + 24

Combine the values to find g(a-2)+3g(2a).

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4 0
3 years ago
En un triangulo ABC, el angulo B mide 64° y el angulo C mide 72°. La bisectriz interior CD corta a la altura BH y a la bisectriz
nadezda [96]

Answer:

The difference between the greatest and the smallest angle of the triangle PBQ is 98°.

Step-by-step explanation:

The question is:

In a triangle ABC, angle B measures 64 ° and angle C measures 72°. The inner bisector CD intersects the height BH and the bisector BM at P and Q respectively. Find the difference between the greatest and the smallest angle of the triangle PBQ.

Solution:

Consider the triangle ABC.

The measure of angle A is:

angle A + angle B + angle C = 180°

angle A = 180° - angle B - angle C

             = 180° - 72° - 64°

             = 44°  

It is provided that CD and BM are bisectors.

That:

angle BCP = angle PCH = 36°

angle CBQ = angle QBD = 32°

angle BHC = 90°

Compute the measure of angle HBC as follows:

angle HBC = 180° - angle BHC + angle BCH

                  = 180° - 90° - 72°

                  = 18°

Compute the measure of angle BPC as follows:

angle BPC = 180° - angle PCB + angle CBP

                  = 180° - 18° - 36°

                  = 126°

Then the measure of angle BPQ will be:

angle BPQ = 180° - angle BPC

                  = 180° - 126°

angle BPQ = 54°

Compute the measure of angle PBQ as follows:

angle PBQ = angle B - angle QBD - angle HBC

                  = 64° - 32° - 18°

angle PBQ = 14°

Compute the measure of angle BQP as follows:

angle BQP = 180° - angle PBQ - angle BPQ

                  = 180° - 14° - 54°  

angle BQP = 112°

So, the greatest and the smallest angle of the triangle PBQ are:

angle BQP = 112°

angle PBQ = 14°

Compute the difference:

<em>d</em> = angle BQP - angle PBQ

  = 112° - 14°

  = 98°

Thus, the difference between the greatest and the smallest angle of the triangle PBQ is 98°.

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Answer:

Step-by-step explanation:

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