The volume of a square pyramid is (1/3)(area of base)(height of pyramid).
Here the area of the base is (10 ft)^2 = 100 ft^2.
13 ft is the height of one of the triangular sides, but not the height of the pyramid. To find the latter, draw another triangle whose upper vertex is connected to the middle of one of the four equal sides of the base by a diagonal of length 13 ft. That "middle" is 5 units straight down from the upper vertex. Thus, you have a triangle with known hypotenuse (13 ft) and known opposite side 5 feet (half of 10 ft). What is the height of the pyramid?
To find this, use the Pyth. Thm.: (5 ft)^2 + y^2 = (13 ft)^2. y = 12 ft.
Then the vol. of the pyramid is (1/3)(area of base)(height of pyramid) =
(1/3)(100 ft^2)(12 ft) = 400 ft^3 (answer)
Answer:
4) 0.001
Step-by-step explanation:
The amount (a) present in h hours is ...
a(h) = (initial value)×(1/2)^(h/(half-life))
6 days is 6×24 hours, so the amount remaining is ...
a(6×24) = 50×(1/2)^(6×24/9) = 50/2^16 ≈ 0.001 . . . . milligrams
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
4037 in standard form
4037=4.037*10^3
Answer: -3
Step-by-step explanation:
Loses means negative. It is getting lesser and if you use a number line and start from zero, you move to the left side of it and get -3. I hope that helps.
