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Marianna [84]
3 years ago
15

Consider the table of the powers of 8. A 1-column table with 6 rows. Column 1 is labeled Power of 8 with entries 8 cubed = 512,

8 squared = 64, 8 Superscript 1 = 8, 8 Superscript 0 = a, 8 Superscript negative 1 = b, 8 Superscript negative 2 = c.
Mathematics
2 answers:
maw [93]3 years ago
8 0

1=b

Step-by-step explanation:

vaieri [72.5K]3 years ago
4 0

Answer:

What is the pattern as the exponents decrease?

✔ divided by 8

What is the value of each variable in the table?

a =  

✔ 1

b =  

✔ 1/8

c =  

✔ 1/64

Step-by-step explanation:

Brainliest pls

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Answer:

Step-by-step explanation:

1. Given the integral function \int\limits {\sqrt{a^{2} -x^{2} } } \, dx, using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as asin \theta i.e x = a sin\theta.

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\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta  } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)}   } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)}   } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)}   } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)}   }}} \, 7cos\theta d\theta\\

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