Can you take a picture of the question so I can solve it
Answer:
an expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable(s).
Answer:
The vertices of image are A'(0,0), B'(-1,-5) and C'(4,-5). The graph of image and preimage is shown below.
Step-by-step explanation:
From the given figure it is noticed that the vertices of triangle ABC are A(0,0), B(1,5) and C(-4,5).
If a figure rotated at 180º about the origin, then

The vertices of image are



Therefore the vertices of image are A'(0,0), B'(-1,-5) and C'(4,-5).
The graph of image and preimage is shown below.
(a-b)^2 = a^2-2ab+b^2
(8-5i)^2 = 8^2-2(8)(5i)+(5i)^2
= 64-80i+25i^2
i^2=-1
So
= 64-80i+25(-1)
=64-25-80i
= <em><u>39 - 80i</u></em>
which is your answer :)
Answer:
+6x-16
Step-by-step explanation:
(x+8)(x+−2)
=(x)(x)+(x)(−2)+(8)(x)+(8)(−2)
=x^2−2x+8x−16
=x^2+6x−16