Given:
Line a is perpendicular to line b
.
Line a passes through the points (1,-8) and (9,-12)
.
Line b passes through the point (-8, -16).
To find:
The equation of b.
Solution:
Line a passes through the points (1,-8) and (9,-12)
. So, slope of line a is
Product of slopes of two perpendicular lines is -1.



Slope of line b is 2.
If a line passing through a point
with slope m, then equation of line is

Line b passing through (-8,-16) with slope 2. So, equation of line b is



Subtract 16 from both sides.

Therefore, the equation of line b is
.
The value of
is 4.
By Geometry, we know that line segment
, which is equivalent to:

(1)
Now we solve algebraically the resulting expression.
If we know that
, then we solve the equation for
:



The value of
is 4.
We kindly invite to see this question on line segments: brainly.com/question/23297288
The first thing you should know in this case is that a circumference has a total measure in 360 degrees.
We have then that the formula to find EG in this case is:
EG + GF + FE = 360
We cleared EG:
EG = 360-GF-FE
We substitute the values:
EG = 360-83-66
EG = 211
Answer
EG = 211 degrees.
F(x) = 2x and G(x) = x^2 + 2
(G - F)(x) just means we subtract the functions from each other.
x^2 + 2 - 2x
Let's rearrange the expression
x^2 - 2x + 2