Answer:
<h3>
aₙ = 3n + 9</h3>
Step-by-step explanation:
![a_1=12\\a_2=15\\\\d=a_2-a_1=15-12=3\\\\a_n=a_1+d(n-1)\\\\a_n=12+3(n-1)\\a_n=12+3n-3\\a_n=3n+9](https://tex.z-dn.net/?f=a_1%3D12%5C%5Ca_2%3D15%5C%5C%5C%5Cd%3Da_2-a_1%3D15-12%3D3%5C%5C%5C%5Ca_n%3Da_1%2Bd%28n-1%29%5C%5C%5C%5Ca_n%3D12%2B3%28n-1%29%5C%5Ca_n%3D12%2B3n-3%5C%5Ca_n%3D3n%2B9)
Step 1. Multiply first equation with -3 and the second one with 2. You'll get:
![\left \{ {{-9x-6y=-12} \atop {8x+6y=14}} \right.](https://tex.z-dn.net/?f=%20%5Cleft%20%5C%7B%20%7B%7B-9x-6y%3D-12%7D%20%5Catop%20%7B8x%2B6y%3D14%7D%7D%20%5Cright.%20)
Step 2. Add both equations together. You'll get:
![-x=2](https://tex.z-dn.net/?f=-x%3D2)
, which gives x = -2
Step 3. Replace x = -2 in the first equation and calculate y.
![3(-2)+2y=4\\ y=\frac{4+6}{2}=5](https://tex.z-dn.net/?f=3%28-2%29%2B2y%3D4%5C%5C%0Ay%3D%5Cfrac%7B4%2B6%7D%7B2%7D%3D5)
The solution is: x=-2, y=5
Answer:
In one month we have to pay an interest of $0.5.
Step-by-step explanation:
We are given that you borrow $60.00 at 10% interest and we have to find how much we have to pay in one month.
Let the Principal sum of money = P = $60
the rate of interest = R = 10%
Time period = T = ![\frac{1}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B12%7D)
Assuming the interest is simple interest, so the formula for simple interest is given by;
Amount = Principal + Simple interest
A = P + (
)
A = ![60 + \frac{60 \times 10 \times 1}{100 \times 12}](https://tex.z-dn.net/?f=60%20%2B%20%5Cfrac%7B60%20%5Ctimes%2010%20%5Ctimes%201%7D%7B100%20%5Ctimes%2012%7D)
A = 60 + 0.5 = $60.5
So, in one month we have to pay an interest of $0.5.