Given the points (–3,k) and (2,0), for which values of k would the distance between the points be √34 ?

Mathematics

2 answers:

myrzilka [38]3 years ago

6 0

Answer:

The values of k are 3 and -3

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$(-3,k)\\(2,0)$

$d=\sqrt{34}$

substitute

$\sqrt{34}=\sqrt{(0-k)^{2}+(2+3)^{2}}$

$\sqrt{34}=\sqrt{(-k)^{2}+(5)^{2}}$

$\sqrt{34}=\sqrt{k^{2}+25}$

squared both sides

$34=k^{2}+25$

$k^{2}=34-25$

$k^{2}=9$

$k=(+/-)3$

Slav-nsk [51]3 years ago

5 0

Answer:

3,-3

Step-by-step explanation:

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Given: the function defined by f(x)=3x^2-4 Which statement is true? 1. f(0) = 0 2. f(-2) = f(2) 3. f(5)+ f(2) = f(7) 4. f(5) x f

sergeinik [125]

$f(x)=3x^2-4 \\ \Downarrow \\ f(0)=3 \times 0^2-4=0-4=-4 \\ -4 \not= 0 \\ f(0) \not= 0 \\
\hbox{statement 1 is false} \\ \\
f(-2)=3 \times (-2)^2-4 =3 \times 4-4=12-4=8 \\
f(2)=3 \times 2^2-4=3 \times 4-4=12-4=8 \\ 8=8
\\ f(-2)=f(2) \\
\hbox{statement 2 is true}$

$f(5)=3 \times 5^2-4=3 \times 25-4=75-4=71 \\ f(2)=8 \\
f(7)=3 \times 7^2-4=3 \times 49-4=147-4=143 \\
71+8 \not= 143 \\
f(5)+f(2) \not= f(7) \\ \hbox{statement 3 is false} \\ \\
f(5)=71 \\ f(2)=8 \\ f(10)=3 \times 10^2-4=3 \times 100-4=300-4=296 \\
71 \times 8 \not= 296 \\
f(5) \times f(2) \not= f(10) \\
\hbox{statement 4 is false}$

Stamement 2. f(-2)=f(2) is true.

3 0

3 years ago

Find the missing segment.

Bond [772]

Answer:

? = 7.

Step-by-step explanation:

The two triangles are similar because of the AA Theorem.

The larger triangle's side that is equal to 9 + 3 corresponds to the smaller triangle's side length of 9, while the larger triangle's 21 + ? side corresponds to the smaller triangle's 21 side. Now, we can set up a proportion!

$\frac{9}{9+3} =\frac{21}{21 + ?}$