Question

Given the points (–3,k) and (2,0), for which values of k would the distance between the points be √34 ?

Answer 1

Answer:

The values of k are 3 and -3

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$(-3,k)\\(2,0)$  

$d=\sqrt{34}$

substitute

$\sqrt{34}=\sqrt{(0-k)^{2}+(2+3)^{2}}$

$\sqrt{34}=\sqrt{(-k)^{2}+(5)^{2}}$

$\sqrt{34}=\sqrt{k^{2}+25}$

squared both sides

$34=k^{2}+25$

$k^{2}=34-25$

$k^{2}=9$

$k=(+/-)3$

Answer 2

Answer:

3,-3

Step-by-step explanation: