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2 years ago

Which expressions are equivalent to -2(5x-1)+7(5x-1)-3(-5x+1)

Mathematics

1 answer:

blondinia [14]2 years ago

8 0

Answer:

x=1/5

Step-by-step explanation:

To solve this question we will have to open the bracket first

So let's go back to the given question

-2(5x-1)+7(5x-1)-3(-5x+1)

We can actually equate the equation to zero

Let's solve

-10x+2+35x-7+15x-3=0

Let's collect like terms

-10x+35x+15x=-2+7+3

40x=8

Let's make x the subject of formula by dividing both sides by 40

x=1/5

So the final answer is 1/5

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A population p of migrating butterflies changes over time it is represented by the equation p=100,000*4/5 where w is the number

Trava [24]

Given that,

A population p of migrating butterflies changes over time it is represented by the equation

$p=100,000\times (\dfrac{4}{5})^w$ Where w is number of weeks.

To find,

The population after 2 weeks.

Solution,

We have,

$p=100,000\times (\dfrac{4}{5})^w$

Put w = 2 in the above equation.

$p=100,000\times (\dfrac{4}{5})^2\\\\=100,000\times \dfrac{16}{25}\\\\=64000$

So, the population after 2 weeks is 64000 .

7 0

3 years ago

Given the function f(x) = x^4 + 3x^3 - 2x^2 - 6x - 1, use intermediate theorem to decide which of the following intervals contai

marta [7]

$f(x) = x^4 + 3x^3 - 2x^2 - 6x - 1$

Lets check with every option

(a) [-4,-3]

We plug in -4 for x and -3 for x

$f(-4) = (-4)^4 + 3(-4)^3 - 2(-4)^2 - 6(-4) - 1= 55$

$f(-3) = (-3)^4 + 3(-3)^3 - 2(-3)^2 - 6(-3) - 1= -1$

f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.

(b) [-3,-2]

We plug in -3 for x and -2 for x

$f(-3) = (-3)^4 + 3(-3)^3 - 2(-3)^2 - 6(-3) - 1= -1$

$f(-2) = (-2)^4 + 3(-2)^3 - 2(-2)^2 - 6(-2) - 1= -5$

f(-2) is negative and f(-3) is negative. there is no value at x=c on the interval [-3,-2] where f(c)=0.

(c) [-2,-1]

We plug in -2 for x and -1 for x

$f(-2) = (-2)^4 + 3(-2)^3 - 2(-2)^2 - 6(-2) - 1= -5$

$f(-1) = (-1)^4 + 3(-1)^3 - 2(-1)^2 - 6(-1) - 1= 1$

f(-2) is negative and f(-1) is positive. there is some value at x=c on the interval [-2,-1] where f(c)=0. so there exists atleast one zero on this interval.

(d) [-1,0]

We plug in -1 for x and 0 for x

$f(-1) = (-1)^4 + 3(-1)^3 - 2(-1)^2 - 6(-1) - 1= 1$

$f(0) = (0)^4 + 3(0)^3 - 2(0)^2 - 6(0) - 1= -1$

f(-1) is positive and f(0) is negative. there is some value at x=c on the interval [-1,0] where f(c)=0. so there exists atleast one zero on this interval.

(e) [0,1]

We plug in 0 for x and 1 for x

$f(0) = (0)^4 + 3(0)^3 - 2(0)^2 - 6(0) - 1= -1$

$f(1) = (1)^4 + 3(1)^3 - 2(1)^2 - 6(1) - 1= -5$

f(0) is negative and f(1) is negative. there is no value at x=c on the interval [0,1] where f(c)=0.

(f) [1,2]

We plug in 1 for x and 2 for x

$f(1) = (1)^4 + 3(1)^3 - 2(1)^2 - 6(1) - 1= -5$

$f(2) = (2)^4 + 3(2)^3 - 2(2)^2 - 6(2) - 1= 19$

f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.

so answers are (a) [-4,-3], (c) [-2,-1], (d) [-1,0], (f) [1,2]

8 0

3 years ago

Read 2 more answers

Jeffrey is going to charge an initial fee of $10 for mowing lawns, plus an hourly rate. He knows that he wants to

zmey [24]

Answer:

B 15

Step-by-step explanation:

10 dollar + 2 hours of work 15 x 2

4 0

3 years ago

Given that (-8,- 7) in on the graph of f(x), find the corresponding point for the fuction f(x -4)

kiruha [24]

The point (x1,y1) on the graph of f(x) is the point (x1-a,y1) for the function
f(x+a)

(-8,-7)=(x1,y1)→x1=-8, y1=-7
f(x-4)=f(x+a)→a=-4

(x1-a, y1)=(-8-(-4), -7)=(-8+4, -7)=(-4,-7)

<span>The corresponding point for the fuction f(x -4) is (-4,-7)</span>

8 0

3 years ago

Mr Wallace sells appliances in receives a weekly salary of $275 plus a 3% Commission on all of his self last week is sells total

Greeley [361]

Answer:

The total earning of Mr Wallace for the week is $310.37

Step-by-step explanation:

Given as :

The fixed weekly salary of Mr Wallace = $275

And The commission of 3% on his total sell

Last week Mr Wallace total sells amount= $1179

I.e 3% of total sells amount = 3% of $1179 = .03 × $1179 = $35.37

∴The total earning = $275 + $35.37 = $310.37

Hence The total earning of Mr Wallace for the week is $310.37 Answer

8 0

3 years ago