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Leokris [45]
4 years ago
12

4. The length of an injected-molded plastic case that holds tape is normally distributed with a mean length of 90.2 millimeters

and a standard deviation of 0.1 millimeters. a. What is the probability that a part is longer than 90.3 millimeters or shorter than 89.7 millimeters
Mathematics
1 answer:
Jet001 [13]4 years ago
4 0

Answer:

Step-by-step explanation:

The length of an injected-molded plastic case that holds tape is normally distributed with a mean length of 90.2 millimeters and a standard deviation of 0.1 millimeters. a. What is the probability that a part is longer than 90.3 millimeters or shorter than 89.7 millimeters

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If 36 is 30%, what is 100%
Sophie [7]
36                30%
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x              100%

Cross multiply and divide
x=120
6 0
3 years ago
Someone help me with 4 pleaseeeeee
Bad White [126]

Answer:

C

Step-by-step explanation:

Use the equation a^2 + b^2 = c^2

Input the numbers----> (2865)^2 +(4550)^2=c^2

Simplify ----> 28910725=c^2

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3 0
2 years ago
Keith drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 8 hours. When Keith drove
Phantasy [73]

Answer:

Keith live 280 miles far way from the mountains.

Step-by-step explanation:

Consider the provided information.

Keith drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took  8  hours.

Let the distance is D and average rate or speed is x miles.

Distance =Speed\times Time

Substitute the respective values.

D=x\times 8\\D=8x

When Keith drove home, there was no traffic and the trip only took  5

hours. The average rate was  21  miles per hour faster on the trip home,

The average rate or speed during return is x+21 miles.

Substitute the respective values in the above formula.

D =(x+21)\times 5\\D=5x+105

Equate both the equations.

5x+105=8x\\3x=105\\x=35

Substitute the value of x in D=8x

D=8(35)\\D=280

Hence, Keith live 280 miles far way from the mountains.

7 0
3 years ago
Solve the system of equations. <br> 13x−y=90 <br> y=x^2−x−42
vfiekz [6]
Solve the first for y

y=13x-90 and the second is y=x^2-x-42

When there is/are solutions y=y so we can say:

x^2-x-42=13x-90  subtract 13x from both sides

x^2-14x-42=-90  add 90 to both sides

x^2-14x+48=0  expand so that it is easy to factor...

x^2-6x-8x+48=0 now factor 1st and 2nd pair of terms

x(x-6)-8(x-6)=0

(x-8)(x-6)=0

So there are two solutions, when x=6 and 8.

Using either original equation we can find the corresponding values for y.  I'll use y=13x-90 because it is easier...

y(6)=-12, y(8)=14  so the two solutions are the points:

(6,-12) and (8,14)


7 0
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Free_Kalibri [48]

Answer:

C. 3/5

Step-by-step explanation:

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3 years ago
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