Round to the nearest tenths Plzz show step by step

Mathematics

1 answer:

zhuklara [117]3 years ago

8 0

So first, separate the triangle from the rectangle. Then calculate the area of the rectangle, length X width. 24 times 8 = 192. Now, for the triangle, we must first find its base. You see the two 6 yd's ??? We add that and we subtract that from 24. We get 12. Since we have to multiply the base times height and divide it by 2 (this is the formula for a triangle), we must find the triangle's height. You can see the red dash going through the shape and it says 16. To the right side of that, we see 8, so we instantly know that the half of that red dash is 8yd. So the triangle's height is 8yd. Multiply 12 by 8 =96. Divide it by two because a triangle is the half of a square, then we get 48yd. Add 48 by 192 and we get 240. The area of this shape is 240 yd.

That was long

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3 years ago

A rectangular enclosure is to be created using 82m rope.

atroni [7]

Let
x-----> the length of rectangle
y-----> the width of rectangle

we know that
perimeter of rectangle=2*[x+y]
perimeter of rectangle=82 m
82=2*[x+y]---> divide by 2 both sides---> 41=x+y--> y=41-x---> equation 1

Area of rectangle=x*y
substitute equation 1 in the area formula
Area=x*[41-x]----> 41x-x²

using a graph tool
see the attached figure

the vertex is the point (20.5,420.25)
that means
for x=20.5 m ( length of rectangle)
the area is 420.25 m²

y=420.25/20.5----> 20.5 m

the dimensions are
20.5 m x 20.5 m------> is a square

the answer part 1)
<span>the dimensions of the rectangular with Maximum area is a square with length side 20.5 meters
</span>
Part 2)<span>b) Suppose 41 barriers each 2m long, are used instead. Can the same area be enclosed?
</span>divide the length side of the square by 2
so
20.5/2=10.25--------> 10 barriers
the dimensions are 10 barriers x 10 barriers
10 barriers=10*2---> 20 m

the area enclosed with barriers is =20*20----> 400 m²

400 m² < 420.25 m²
so

the answer Part 2) is
<span>the area enclosed by the barriers is less than the area enclosed by the rope
</span>
Part 3)<span>How much more area can be enclosed if the rope is used instead of the barriers
</span>
area using the rope=420.25 m²
area using the barriers=400 m²

420.25-400=20.25 m²

the answer part 3) is
20.25 m²

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3 years ago

The information below applies to a competitive firm that sells its output for $40 per unit.

drek231 [11]

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

On producing 150 units, its average total cost = $24.50

We need to find the total cost.

As we know that

$Average\ cost=\dfrac{Total\ cost}{No.\ of\ units}\\\\total\ cost=Average\ cost\times No.\ of\ units\\\\total\ cost=24.50\times 150\\\\total\ cost=\$3675$

Hence, total cost is $3675.00.

Therefore, Option 'c' is correct.

3 0

3 years ago

Is the set of integers closed under division? Explain why or why not.

MrMuchimi

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<h3>How to determine the true statement?</h3>

Integers are numbers without decimal points

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Zero
Decimal
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This is so because when an integer is divided by another, the results are not limited to only integers i.e. zero and decimals are possibilities