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Kobotan [32]
3 years ago
6

How to simplify this expression

Mathematics
1 answer:
dexar [7]3 years ago
5 0

Answer:

  \dfrac{x+2}{x+1}

Step-by-step explanation:

Factor the numerator and cancel common factors from numerator and denominator.

  \dfrac{x^2-4}{(x-2)(x+1)}=\dfrac{(x-2)(x+2)}{(x-2)(x+1)}=\dfrac{x+2}{x+1}

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What is a 15 of the sequence -7, 2, 11, ...?<br><br> A. 128<br> B. 110<br> C. 136<br> D. 119
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Answer:

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Step-by-step explanation:

To find the common difference, we take the second term and subtract the first term

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The common difference is 9

The formula for an arithmetic sequence is

an = a1 +d(n-1)

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a1=-7, d=9 and we are looking for the 15th term  so n=15

a15 = -7 +9(15-1)

a15 = -7+9(14)

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