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Phoenix [80]
3 years ago
10

A rectangle has a height of 2 and a width of 5x^2-2x+3

Mathematics
1 answer:
ivann1987 [24]3 years ago
7 0

Answer:

I believe its 12x^2

Step-by-step explanation:

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The product of 60 and 4000 is
svlad2 [7]

Answer:

The product of 60 and 4000 is 240,000

Step-by-step explanation:

If you are asked to work out the product of two or more numbers, then you need to multiply the numbers together.

7 0
3 years ago
Read 2 more answers
HRLPPPPP IM FAILING MATHH
Gemiola [76]
It’s the third one

B=50.27 cm
V=371.97
7 0
3 years ago
The perimeter of a rectangle is equal to the sum of its sides.If the length of a a rectangle is twice its width and the perimete
8_murik_8 [283]

Answer: the width of the rectangle

= 31feet.

Step-by-step explanation:

Perimeter of a triangle = 2( l + b)

let the width = xfeet

The length = 2x feet.

Substitute for this in the equation above,

2( 2x + x ) = 186

2(3x) = 186

Divide by 2 through

3x = 93

Divide by 3

x = 31feet. Therefore, the width of the rectangular = 31feet.

Check.

Since the length is twice the width,

L = 31 x 2

= 62feet.

Put that into the formula above

2( 62 + 31 )

2 x 93

= 186 which is the perimeter of the rectangle.

3 0
3 years ago
Esplain how to find 30×80 using mental math
Artemon [7]
You ignore the 0's for now and think of 3 x 8 instead
3 x 8 = 24
with the answer of 24, you would now attach the two 0's
2400
2400 is your answer
6 0
4 years ago
5. Verify the property a× (b-c)= a×b-a×c for each of the following:<br>a= -3\5; b= 5\9; c= -10\3​
ohaa [14]

Answer:

We conclude that

a\times \left(b-c\right)=\:a\times b-a\times c

           -\frac{7}{3}=-\frac{7}{3}

        L.H.S = R.H.S    

Step-by-step explanation:

Given the property expression

a\times \left(b-c\right)=\:a\times b-a\times c

Given that:

  • a = -3/5
  • b = 5/9
  • c = -10/3

<u>Determining the LEFT-HAND SIDE</u>

a\times \left(b-c\right)

substituting a= -3/5, b= 5/9 and c= -10/3​

a\times \left(b-c\right)\:=\:\:-\frac{3}{5}\times \left(\frac{5}{9}-\left(-\frac{10}{3}\right)\right)\:\:\:\:\:\:\:\:\:\:\:\:

                  =-\frac{3}{5}\times \:\left(\frac{5}{9}+\frac{10}{3}\right)\:\:\:

                  =-\frac{3}{5}\times \frac{35}{9}

                   =-\frac{7}{3}

<u>Determining the RIGHT-HAND SIDE</u>              

\:a\times \:b-a\times \:c

substituting a= -3/5, b= 5/9 and c= -10/3​

\:a\times \:b-a\times \:c=ab-ac

                      =-\frac{3}{5}\left(\frac{5}{9}\right)-\left(-\frac{3}{5}\right)\left(-\frac{10}{3}\right)

                      =-\frac{3}{5}\cdot \frac{5}{9}-\frac{3}{5}\cdot \frac{10}{3}

                      =-\frac{15}{45}-\frac{30}{15}

                      =-\frac{1}{3}-2

                      =\frac{-7}{3}

Apply the fraction rule:  \frac{-a}{b}=-\frac{a}{b}

                      =-\frac{7}{3}

Therefore, we conclude that

a\times \left(b-c\right)=\:a\times b-a\times c

           -\frac{7}{3}=-\frac{7}{3}

        L.H.S = R.H.S                                          

5 0
3 years ago
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