Answer:
First box: 2
Second box: 30
Third box: 42
Step-by-step explanation:
5 sixes means 5 · 6, which equals 30. An unknown amount of sixes equals 12, which is 2 because 2 · 6 = 12.
30 + 12 = 42
7 · 6 = 42, so 42 is the answer.
I hope this helped! :)
Y = |x² - 3x + 1|
y = x - 1
|x² - 3x + 1| = x - 1
|x² - 3x + 1| = ±1(x - 1)
|x² - 3x + 1| = 1(x - 1) or |x² - 3x + 1| = -1(x - 1)
|x² - 3x + 1| = 1(x) - 1(1) or |x² - 3x + 1| = -1(x) + 1(1)
|x² - 3x + 1| = x - 1 or |x² - 3x + 1| = -x + 1
x² - 3x + 1 = x - 1 or x² - 3x + 1 = -x + 1
- x - x + x + x
x² - 4x + 1 = -1 or x² - 2x + 1 = 1
+ 1 + 1 - 1 - 1
x² - 4x + 1 = 0 or x² - 2x + 0 = 0
x = -(-4) ± √((-4)² - 4(1)(1)) or x = -(-2) ± √((-2)² - 4(1)(0))
2(1) 2(1)
x = 4 ± √(16 - 4) or x = 2 ± √(4 - 0)
2 2
x = 4 ± √(12) or x = 2 ± √(4)
2 2
x = 4 ± 2√(3) or x = 2 ± 2
2 2
x = 2 ± √(3) or x = 1 ± 1
x = 2 + √(3) or x = 2 - √(3) or x = 1 + 1 or x = 1 - 1
x = 2 or x = 0
y = x - 1 or y = x - 1 or y = x - 1 or y = x - 1
y = (2 + √(3)) - 1 or y = (2 - √(3)) - 1 or y = 2 - 1 or y = 0 - 1
y = 2 - 1 + √(3) or y = 2 - 1 - √(3) or y = 1 or y = -1
y = 1 + √(3) or y = 1 - √(3) (x, y) = (2, 1) or (x, y) = (0, -1)
(x, y) = (2 ± √(3), 1 ± √(3))
The solution (0, -1) can be made by one function (y = x - 1) while the solution (2 ± √(3), 1 ± √(3)) can be made by another function (y = |x² - 3x + 1|). So the solution (2, 1) can be made by both functions, making the two solutions equal.
Answer: I believe its 24 meters.
Explanation: Just divide 120 by 5
The answer is $213 because you subtract the price sold by the price he bought them for and then you add them together (see work)
Complete question is;
Andrea is given ABC and told that a² + b² = c². She draws right triangle RTS with legs measuring a and b and hypotenuse measuring 2. Which best describes what Andrea should
do in order to prove that ABC is a right triangle?
Answer:
Andrea should show that c = 2, so: ∡ABC = ∡RTS and ∡C = ∡S. Hence, ∡C is a right angled triangle, hence ΔABC is a right triangle
Step-by-step explanation:
In this question, we are told that the given sides of the triangle are a, b and c. Now, Andrea is able to draw the two sides of the right triangle with sides = a and b and the third, hypotenuse equal to 2. Since the length of the hypotenuse = 2, then we have;
2² = a² + b²
However, we are told that c² = a² + b²
Therefore, c = 2
Hence, Andrea should show that c = 2 so ΔABC = ΔRTS and ∡C = ∡S hence ∡C is a right angled triangle since it is the angle opposite to the hypotenuse c and therefore, ΔABC is a right triangle.
