3 years ago

A stock was purchased at $15.75 per share, and sold at $19.25 per share What was the net profit per share?

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

6 0

It. Is. (19.25-15.75)/15.75

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nataly862011 [7]

5-12 ÷(6-2)-1

Do whats in the parenthesis

5-12 ÷4-1

Do division next

5- 3- 1 = 1.

Do the same for the next.

(4-3) x 2+15 ÷(6-1)

1 x 2+15 ÷5

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2+3= 5

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Answer:

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Now, Putting the value of x=5

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Step-by-step explanation:

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1 year ago

For a regular 15-sided polygon, what is the degree of rotation?

Volgvan

Hope this helps! :)
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3 years ago

find the Taylor Series for tan−1(x) based at 0. Give your answer using summation notation and give the largest open interval on

enyata [817]

Let $f(x)=\tan^{-1}x$ . Then $f'(x)=\frac1{1+x^2}$ . Note that $f(0)=0$ .

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{n\ge0}x^n$

This means that for $|-x^2|=|x|^2$ , or $-1$ , we have

$\displaystyle f'(x)=\frac1{1+x^2}=\frac1{1-(-x^2)}=\sum_{n\ge0}(-x^2)^n=\sum_{n\ge0}(-1)^nx^{2n}$

Integrate the series to get

$f(x)=f(0)+\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}$

$\implies\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}$

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