We know the total distance and individual times, so we can sum and equate total distance.
Let
E=speed heading east
E+45=speed heading south
then
4(E+45)+6E=3370 miles
Solve for E:
4E+180+6E=3370
10E=3370-180=3190 mph
E=319 mph.
In the construction of the equilateral triangle EFG inscribed in a circle, Chase can find points F and G as D. Points F and G are points of intersection of two congruent circles centered at D and E.
<h3>What is an equilateral triangle?</h3>
It should be noted that an equilateral triangle simply means a triangle that has all the sides and angles to be equal.
After drawing the diameter of the circle through the center, it's important to open the compass to a width that's equivalent to the radius the circle.
In this case, it can be deduced that Points F and G are points of intersection of two congruent circles centered at D and E.
Learn more about triangles on:
brainly.com/question/17335144
The boat(x) goes 1mi/hr because 4 mi and 4hr divide each by four. The rate of the river current S twice that because the time is halved so y=8mi/hr
D is the only viable answer among these, as A, B, and C all contain two even integers which, by definition, have a greatest common factor of 2.
<em>Correction: </em>I was incorrect in saying that <em>all </em>even integers have a greatest common factor of 2; 2 is at least guaranteed to be <em>one of the common factors </em>in any group of even numbers, but these examples all have it as their <em>greatest </em>common factor as well.
