Number 4 would be: C
And number 5 would be: C
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Check the picture below.
so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).
because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,
![\bf \textit{hyperbolas, vertical traverse axis } \\\\ \cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h, k\pm a)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2}\\ asymptotes\quad y= k\pm \cfrac{a}{b}(x- h) \end{cases}\\\\ -------------------------------](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bhyperbolas%2C%20vertical%20traverse%20axis%20%7D%0A%5C%5C%5C%5C%0A%5Ccfrac%7B%28y-%20k%29%5E2%7D%7B%20a%5E2%7D-%5Ccfrac%7B%28x-%20h%29%5E2%7D%7B%20b%5E2%7D%3D1%0A%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Acenter%5C%20%28%20h%2C%20k%29%5C%5C%0Avertices%5C%20%28%20h%2C%20%20k%5Cpm%20a%29%5C%5C%0Ac%3D%5Ctextit%7Bdistance%20from%7D%5C%5C%0A%5Cqquad%20%5Ctextit%7Bcenter%20to%20foci%7D%5C%5C%0A%5Cqquad%20%5Csqrt%7B%20a%20%5E2%20%2B%20b%20%5E2%7D%5C%5C%0Aasymptotes%5Cquad%20%20y%3D%20k%5Cpm%20%5Ccfrac%7Ba%7D%7Bb%7D%28x-%20h%29%0A%5Cend%7Bcases%7D%5C%5C%5C%5C%0A-------------------------------)
Answer: 35.52
Step-by-step explanation:
Answer:
6b^4+6b^3-923
Step-by-step explanation:
First year 100x0.05 = 5
Second year 100x0.05 = 5
Third year 100x0.05 = 5
Total interest 15$ for three year + the original amount mean 100
Total after three year
$115
Because the interest not compounded mean : where previously accumulated interest is not added to the principal amount of the current period, so there is no compounding.