What side is this a isosceles a scalene or equilateral

Find the perimeter of the shape with vertices (2, 3), (5, 3) and (5, 7).

topjm [15]

Answer:

right triangle with sides 3,4,& 5

perimeter=12

Step-by-step explanation:

6 0

2 years ago

Use the standard algorithm to find the product of 853 and 59. Record the product of multiplying by the ones digit, the product o

bearhunter [10]

The product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650 and the final product is 50327

<h3>How to determine the product of the numbers?</h3>

The numbers are given as

853 and 59

By using the standard algorithm i.e. the partial product method, we have the following equation

853 * 59 = 853 * (50 + 9)

Open the bracket

So, we have

853 * 59 = 853 * 50 + 853 * 9

Evaluate the products

So, we have

853 * 59 = 42650 + 7677

The above means that the product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650

Next, we evaluate the sum

853 * 59 = 50327

This means that the final product is 50327

Read more about products at

brainly.com/question/10873737

#SPJ1

4 0

1 year ago

Olivia picked 482 apples from the orchard’s largest apple tree. She divided the apples evenly into 4 baskets. How many apples ar

Verdich [7]

Answer:

120 with 2 left over

Step-by-step explanation:

482/4 equals 120.5 so each basket gets 120 and then .5+.5+.5+.5= 2 whole extra apples

7 0

2 years ago

Read 2 more answers

39-50 find the limit.<br> 41. <img src="https://tex.z-dn.net/?f=%5Clim%20_%7Bt%20%5Crightarrow%200%7D%20%5Cfrac%7B%5Ctan%206%20t

Katyanochek1 [597]

Write tan in terms of sin and cos.

$\displaystyle \lim_{t\to0}\frac{\tan(6t)}{\sin(2t)} = \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)}$

Recall that

$\displaystyle \lim_{x\to0}\frac{\sin(x)}x = 1$

Rewrite and expand the given limand as the product

$\displaystyle \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)} = \lim_{t\to0} \frac{\sin(6t)}{6t} \times \frac{2t}{\sin(2t)} \times \frac{6t}{2t\cos(6t)} \\\\ = \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right)$

Then using the known limit above, it follows that

$\displaystyle \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right) = 1 \times 1 \times \frac3{\cos(0)} = \boxed{3}$

4 0

1 year ago

Cheyenne's bi-weekly gross pay is $529.81. She sees that $18.54 was deducted for Medicare tax. What percent of Cheyenne's gross

Dafna1 [17]

18.54/529.81= 0.0349
0.0349*100=3.49%= 3.5%

6 0

2 years ago