Here are some factors of 20!
1x20=20
2x10=20
4x5=20
5x4=20
Therefore there are 4 factors of 20.
<u>Answer-</u>
<em>The polynomial function is,</em>

<u>Solution-</u>
The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1
The general form of the equation will be,
( ∵ (3-i) is the conjugate of (3+i) )








Therefore, this is the required polynomial function.
There isn't enough info to prove the triangles to be congruent or not. So we can't say for sure either way.
We have angle CAD = angle ACB given by the arc markings, and we know that AC = AC due to the reflexive theorem. However we are missing one third piece of information.
That third piece of info could be....
- AD = BC which allows us to use SAS
- angle ACD = angle CAB which allows us to use ASA
- angle ABC = angle CDA which allows us to use AAS (slight variation of ASA)
Since we don't know any of those three facts, we simply don't have enough information.
side note: If AB = CD, then this leads to SSA which is not a valid congruence theorem. If we had two congruent sides, the angle must be between the two sides, which is what AD = BC allows.
I only see one question.
The answer is the root 4 has the multiplicity of 2.
Answer:
8.25 pounds
Step-by-step explanation:
Its $3 per pound, so 24.75/3= 8.25