Assuming both vertical lines are parallel and assuming I'm supposed to find all the unmarked angles...
Angle C:
Supplementary Angles.
x+36=180
180-36=x
x=144
Angle B:
Corresponding Angles.
Angle B ≅ Angle C
144
Angle A:
360 degrees in a quadrilateral
36+144+81+x=360
261+x=360
x = 99
<em>Hope it helps <3</em>
Answer:
A. 17
Step-by-step explanation:
using the cosine rule (also see attached for reference):
AB² = BC² + AC² - 2·AC·BC cos C
2·AC·BC cos C = BC² + AC² - AB²
Given that AC = 18, AB = 12 and BC = 18, substituting these into the formula
2(18)(28) cos C = 28² + 18² - 12²
1008 cos C = 964
cos C = 964/1008
cos C = 0.9563
C = cos⁻¹ 0.9563
C = 16.99 ( = 17° rounded to nearest degree)
37 * 48 = 3 * (c - 140 )+ 2 *(c - 140 ) + ( c - 140 ) =>
37 * 48 = 6 * ( c - 140 ) =>
37 * 48 / 6 = c - 140 =>
37 * 8 = c - 140 =>
296 = c - 140 =>
c = 296 + 140 =>
c = 436 ounces.
<u>(-2)+2=0, (-0.5)+0.5=0, and (-5)+5=0</u>
All those equations answers are 0, please mark me brainiest, and hope I helped!
The answer is:
The measure of an exterior angle of a triangle is equal to the sum of the measures of the remote interior angles.
