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3 years ago

I dont know!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

djyliett [7]3 years ago

3 0

Answer:

9in2

Step-by-step explanation:

the 2 is an expononent.

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The pinata weighs 11/4 pounds without candy.He adds 8bags that weighs 3/8,3/8,1/2,1/2,1/2,3/4,3,11/4 how much will the pinata we

Natalka [10]

Answer:

$Weight = \frac{23}{2}$

Step-by-step explanation:

Given

Weight of Pinata = 11/4 lb

Weight of candies = 3/8, 3/8, 1/2 , 1/2, 1/2, 3/4, 3, 11/4

Required

Weight of Pinata when filled with candies

To solve this question, we simply need to add all weights together

First, we need to add up the weight of the candies

$Candies = \frac{3}{8} + \frac{3}{8} + \frac{1}{2}+ \frac{1}{2}+ \frac{1}{2}+ \frac{3}{4} + 3 + \frac{11}{4}$

Take LCM

$Candies = \frac{3 + 3 + 4 +4 + 4 + 6 + 24 + 22}{8}$

$Candies = \frac{70}{8}$

Simplify:

$Candies = \frac{35}{4}$

Next; Add the weight of the candies to the weight of pinata

$Weight = Candies + Pinata$

$Weight = \frac{35}{4} + \frac{11}{4}$

Take LCM

$Weight = \frac{35 + 11}{4}$

$Weight = \frac{46}{4}$

Simplify

$Weight = \frac{23}{2}$

<em>Hence, the weight of the Pinata after it is filled with candies is 23/2 lb</em>

4 0

3 years ago

Every sixth visitor to the bookstore get a free calendar. Every twentieth visitor gets a free book. Which visitor each day will

Neko [114]

The 60 visitor will get the calendar and a book.

6 0

3 years ago

Read 2 more answers

What is the equation of the line that passes through the points (-1, 1.5) and (0.5, 0.5)

Step2247 [10]

The slope-point formula:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have:

$(-1,\ 1.5)\to x_1=-1,\ y_1=1.5\\(0.5,\ 0.5)\to x_2=0.5,\ y_2=0.5$

Substitute:

$m=\dfrac{0.5-1.5}{0.5-(-1)}=\dfrac{-1}{1.5}=-\dfrac{1}{\frac{3}{2}}=-\dfrac{2}{3}\\\\y-1.5=-\dfrac{2}{3}(x-(-1))\\\\y-1.5=-\dfrac{2}{3}x-\dfrac{2}{3}\\\\y-\dfrac{3}{2}=-\dfrac{2}{3}x-\dfrac{2}{3}\ \ \ |+\dfrac{3}{2}\\\\y=-\dfrac{2}{3}x-\dfrac{2}{3}+\dfrac{3}{2}\\\\y=-\dfrac{2}{3}x-\dfrac{2\cdot2}{3\cdot2}+\dfrac{3\cdot3}{2\cdot3}\\\\y=-\dfrac{2}{3}x-\dfrac{4}{6}+\dfrac{9}{6}\\\\y=-\dfrac{2}{3}x+\dfrac{5}{6}$