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Westkost [7]
3 years ago
5

If x=9 and y=3 then |1-2x|+4y^2

Mathematics
1 answer:
trasher [3.6K]3 years ago
8 0

Answer:

53

Step-by-step explanation:

If x = 9 and y = 3, then we have to find the value of |1 - 2x| + 4y^{2}.

The problem is simple and we have to put the values of x and y in the expression.

Let, A = |1 - 2x| + 4y^{2}.

⇒ A = |1 - 2(9)| + 4(3)^{2}

⇒ A = |1 - 18| + 4\times (9)

⇒ A = |- 17| + 36

[Here, we must define the function |x|.

|x| = x for x ≥ 0 and |x| = - x for x < 0

Now, here x is less than zero and it is - 17.

So. |x| = - x = - ( -17) = 17 ]

⇒ A = 17 + 36  

⇒ A = 53 (Answer)

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The coordinates of four points of Quadrilateral ABCD are

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AB=\sqrt{(4+7)^2+(5+10)^2}\\\\AB=\sqrt{121+225}\\\\AB=\sqrt{346}\\\\BC=\sqrt{(-7+4)^2+(-10+9)^2}\\\\BC=\sqrt{9+1}\\\\BC=\sqrt{10}\\\\CD=\sqrt{(4+7)^2+(5+10)^2}\\\\CD=\sqrt{121+225}\\\\CD=\sqrt{346}\\\\DA=\sqrt{(7-4)^2+(6-5)^2}\\\\DA=\sqrt{9+1}\\\\DA=\sqrt{10}

Slope between two points is given by

 m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\m_{1}=\frac{-10-5}{-7-4}\\\\=\frac{-15}{-11}\\\\m_{1}=\frac{15}{11}\\\\m_{2}=\frac{-9+10}{-4+7}\\\\m_{2}=\frac{1}{3}\\\\m_{3}=\frac{6+9}{7+4}\\\\m_{3}=\frac{15}{11}\\\\m_{4}=\frac{6-5}{7-4}\\\\m_{4}=\frac{1}{3}

As slope of opposite sides are equal and length of Opposite sides are equal.So,the given Quadrilateral is a Parallelogram.

Option A

Yes; The opposite sides are congruent and have the same slope.

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