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erik [133]
3 years ago
5

What is 481,026.03 in expanded form using powers of ten.

Mathematics
1 answer:
Ivan3 years ago
8 0

When putting 481,026.03 into expanded form, the answer is 4.8102603 × 10^5, or using a calculator, 4.8102603e5.

Hope this helped!

Nate

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A certain three​-cylinder combination lock has 60 numbers on it. To open​ it, you turn to a number on the first​ cylinder, then
statuscvo [17]

Answer:

(a) The number of different lock combinations is 216,000.

(b) The probability of getting the correct combination in the first try is \frac{1}{216000}.

Step-by-step explanation:

The lock has three-cylinder combinations with 60 numbers on each cylinder.

The procedure of the opening lock is to turn to a number on the first​ cylinder, then to a second number on the second​ cylinder, and then to a third number on the third cylinder.

The numbers can be repeated.

(a)

There are three cylinder combinations on the lock, each with 60 numbers.

It is provided that repetitions are allowed.

Then each cylinder can take any of the 60 numbers.

So there are 60 options for the first cylinder.

There are 60 options for the second cylinder.

And there are 60 options for the third cylinder.

So the total number of possible combinations is:

Total number of combinations = 60 × 60 × 60 = 216000.

Thus, the number of different lock combinations is 216,000.

(b)

The events of getting a correct combinations of the three​-cylinder combination lock implies that all the three cylinder are set at the correct numbers.

Each cylinder has 60 numbers.

This implies that there are 60 possible ways to get a correct number for the first cylinder.

The probability of getting the correct number for the first cylinder is:

P (Number on 1st cylinder is correct) = \frac{1}{60}.

Similarly for the second cylinder the probability of getting the correct number is:

P (Number on 2nd cylinder is correct) = \frac{1}{60}.

And similarly for the third cylinder the probability of getting the correct number is:

P (Number on 3rd cylinder is correct) = \frac{1}{60}.

So the probability of getting the correct combination in the first try is:

P (Correct combination in the 1st try) = \frac{1}{60}\times \frac{1}{60}\times \frac{1}{60}=\frac{1}{216000}.

Thus, the probability of getting the correct combination in the first try is \frac{1}{216000}.

7 0
3 years ago
Help plsss!?!?!??!?!??&gt;...................................
Soloha48 [4]

Answer:

A,B,D

Step-by-step explanation:

case A) If the price is marked down by  percent, the new price will be

we know that

If the price is marked down by 10  percent

then the new price will be

10%= 10/100=0.10

(1 - 0.10) *$28= 0.90 * $28

=$25.20

therefore The statement case A) is True

case B) If the price is marked down by 25 percent, the new price will be $21

we know that

If the price is marked down by 25 percent

then the new price will be

25%=25/100=0.25

(1-0.25)* $28=0.75*$28

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therefore The statement case B) is True

case C) If the price is marked down by 50 percent, the new price will be $19 we know that

If the price is marked down by 50 percent

then the new price will be

50%=50/100=0.50

(1-0.50)*$28= 0.50*$28

=14

therefore The statement case C) is False

case D) If the price is marked down by  35 percent, the new price will be $18.20

we know that

If the price is marked down by 35 percent

then the new price will be

35%= 35/100=0.35

(1-0.35)* $28=0.65*$28

=18.20

therefore The statement case D) is True

case E) If the price is marked down by 40 percent, the new price will be $29.80 we know that

If the price is marked down by 40 percent

then the new price will be

40%=40/100=0.40

(1-0.40)*$28= 0.60*$28

=$16.80

therefore The statement case E) is False

7 0
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