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Black_prince [1.1K]
3 years ago
14

Find the value of x. Please help!

Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0

Answer:

x = 3

Step-by-step explanation:

Using the triangle similarity theorem

x/x+3 = x+3/12

Cross multiply

12x = (x+3)(x+3)

12x = x²+3x+3x+9

12x =  x²+6x+9

x²+6x+9-12x = 0

x²-6x+9 = 0

Factorize

x²-3x-3x+9 = 0

x(x-3)-3(x-3) = 0

x - 3 = 0

x = 3 twice

Hence the value of x is 3

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Mr. Samson deposited some money into his checking account. Then after spending $33, the balance in his account was $67. How much
pochemuha

Answer:

He deposited $100

Step-by-step explanation:

67 + 33 = 100

Hope this helps! Please mark brainliest!

4 0
3 years ago
The area of a trapezoid with height z is 20 sq .cm. The length s of the parallel sides are (2z+3) and (6z-1) cm. Find the height
const2013 [10]

Answer:

Area of a trapezoid = ½(a + b)h, where a and b are the lengths of the parallel sides and h is its height. 

From your information 20 = ½(2z + 3 + 6z – 1)z = ½(8z + 2)z = z(4z + 1) 

Solve 20 = 4z² + z which is 0 = 4z² + z – 20 using the quadratic formula 

Step-by-step explanation:

6 0
3 years ago
Find the parallel line to 5y-15x=-20 that goes through the point (3,-6).
Shtirlitz [24]
5y-15x=-20
5y=15x-20
y=3x-20/3
Slope = 3

Slope Intercept Form
y-y1=m(x-x1)
Therefore y-(-6)=3(x-3)
y+6=3x-9
y=3x-15
8 0
3 years ago
10m/
AlladinOne [14]

Answer:

Answer is D 312m^2

As  D= 8m x 11m = A =88x 3 = 264+ 48 = 312

1/2 x 6 x 8 = 24

This makes triangle base of 6m

triangle side =8m

Rectangle side = 8m

and rectangle length = 11m

Step-by-step explanation:

First finding

A= 6 x 11 = 66m^2 (rectangle area) or 10 x 9 = 90sq^2

A = 1/2 x 6 x 11 = 33  (1/2bh) triangle

33+ 33 + 66 +66 + 66 = 264  or 33+ 33+ 90+90+90 =336

As 336 was not in the answer we do not know what 10m/9m represents, we then see this triangle prism is not a normal shape and its length is same as its height

a) is not in usual proportions.

We try again reversing which makes triangle sides 10m+ base 9m

= 1/2 x 10 x 10 = 50m^2 = triangle face area

we cannot continue the reverse as the triangle sides do not match the rectangle height. We therefore have to use the first answer C 264m^2

As 10m, 9m <do not match >6m 11m 8m

However if the given sizes 10m, 9m = bases of two different rectangles we would calculate 2 faces and add them each to one unknown face being one of the other face sizes we found to make 3.

10 x 8 = 80

9 x 8 = 72

To make one of these SA totals for rectangles alone

=80+80+72=232   or  72+72+80 =224

Then add to the 33 m^2 triangles

= 232+ 33+ 33 =297m^2

= 224+33+33 =310m^2

We can now determine that these measurements represent irregular values and are not answers within multiple choice, however d)  we can state the triangle is regular prism where triangle sides are regular too creating isosceles triangle 6,8,8,

8m x 11m = A =88x 3 = 264+ 48 = 312

1/2 x 6 x 8 = 24

As we have ruled out rectangle with side 8m x 11m + A (33m^2) of triangle would equal 310m^2 (88+88+88+33+33) =330m

And ruled out rectangle with side 8m x 6m= 48m^2 (48+48+48+33+33 =210sqm)

So therefore if triangles were to equal 1/2 x 6 x 8 = 24

24 x 3= 72sqm

add the rectangle amounts above

= 72 + 88+ 88+ 88 =336^2

try another way and we find D. here below.

answer D= 72+ 80+80+80 = 312m^2 this can makes a correct answer D.

As last rule out is;

72 + 72 +72  (+triangle of 72) =288^2 would be irregular as this is equal to (9 x 8) x 3 and then the 11m is not used. It is also not a listed answer. Therefore;  D=312m^2 is correct.

A triangular prism has three rectangular sides and two triangular faces. To find the area of the rectangular sides, use the formula A = lw, where A = area, l = length, and h = height. To find the area of the triangular faces, use the formula A = 1/2bh, where A = area, b = base, and h = height.

3 0
3 years ago
Abigail wrote the statements shown in the chart. . Statement. Description. . 1. If two lines intersect, then exactly one plane c
Lilit [14]

The <u>correct answer</u> is:


B) Statement 1 and Statement 2 are theorems because they can be proved with the help of appropriate postulates.


Explanation:


<u>Statement 1</u> is the Line Intersection Theorem. To prove this, we use postulates about having only one plane passing through any 3 noncollinear points. We would choose two points from one line and one point from the second; they would be non-collinear points and be in one plane. This also works choosing the points the opposite way.


<u>Statement 2</u> is the Point and Line Contained in Plane Theorem. Again, if two lines intersect, we can choose three points to define a plane. We have to prove that both lines are in the plane. We rely on previously proven postulates to do this.

4 0
3 years ago
Read 2 more answers
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