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Lynna [10]
3 years ago
5

Louis wants to carpet the rectangular floor of his basement. The basement has an area of 864 square feet. The width of the basem

ent is Ask Your Teacher its length. What is the length of Louis’s basement?
Mathematics
1 answer:
Over [174]3 years ago
7 0
29.3938769134 ft

Take the radical of 864 to get an answer based on the limited info provided.
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Follow the process of completing the square to solve 2x2 + 8x - 12 = 0.
Rom4ik [11]
Please:  Use "^" to denote exponentiation:  <span>2x^2 + 8x - 12 = 0

Reduce this by div. every term by 2:             </span><span>x^2 + 4x - 6 = 0

Here a=1, b=4 and c = -6.  Square half of b, obtaining (4/2)^2 = 4, and add, and then subtract, this 4 to x^2 + 4x - 6:

</span> x^2 + 4x +4  - 4 - 6 = 0.  Rewrite the square as (x+2)^2, obtaining new equation

(x+2)^2 = 10.  Take the sqrt of both sides:   x+2 = plus or minus sqrt(10).

Finally, solve for x:  x = -2 plus or minus sqrt(10).



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3 years ago
How to find x please help
o-na [289]
You know the adjacent and you need to find the opposite, so you would use tangent. Your equation would look like this; tan 26°= x/28. You would need to multiply both sides by 28 to simplify it to this; 28*tan 26°= x
Solving this, you would get an answer of 13.7
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3 years ago
The 2 legs of a right triangle are 6' and 8' long what is the perimeter of the triangle
Vlad1618 [11]

Answer:24 feet

Step-by-step explanation:

8 0
2 years ago
Suppose f (x) = x^2. Find the graph of f(x+2)
NISA [10]
\bf ~~~~~~~~~~~~\textit{function transformations}&#10;\\\\\\&#10;% templates&#10;f(x)={{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\\\&#10;~~~~y={{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\\\&#10;f(x)={{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\\\&#10;f(x)={{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\\\&#10;f(x)={{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\\\\&#10;--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\&#10;~~~~~~\textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\&#10;~~~~~~\textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;~~~~~~if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;~~~~~~if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;~~~~~~if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind,

\bf f(x)=x^2\qquad \quad f(x+2)=(x+2)^2\implies f(x+2)=\stackrel{A}{1}(\stackrel{B}{1}x\stackrel{C}{+2})^2\stackrel{D}{+0}

C = 2         B = 1        C/B = 2/1 or +2,    horizontal left shift of 2 units

f(x) shifted left by 2 units is f(x+2).
8 0
3 years ago
49–2ax –a^2–x^2 factor
vampirchik [111]

49–2ax –a^2–x^2

Extract the negative sign

= 49 - (a^2 +2ax +x^2)

Factor using a^2 + 2ab + b^2 = (a+b)^2

= 49 - (a+x)^2

Factor using a^2 - b^2 = (a-b)(a+b)

= ( 7- (a + x)) * (7 + (a + x))

= ( 7- a - x) * (7 + a + x)

4 0
3 years ago
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