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Karo-lina-s [1.5K]
3 years ago
14

the perimeter of a rectangular field is 346 yards if the length of the field is 92 yards what is its width

Mathematics
2 answers:
MrMuchimi3 years ago
8 0

\boxed {\text {Perimeter = Length + Length + Width + Width}}

<u>Given that Length = 92 and Perimeter = 346:</u>

346 = 92 + 92 + Width + Width

<u>Combine like terms:</u>

346 = 162 + 2Width

<u>Subtract 162 from both sides:</u>

2Width = 162

<u>Divide both sides by 2:</u>

Width = 81

Answer: Width = 81 yards

Maslowich3 years ago
4 0

the formula for the perimeter of a rectangle is

P= 2(L+W)

with L representing length and W representing width

since we have the perimeter and the length, we can plug the values into the equation to find W

346 = 2(92+w)

346 = 184 + 2W

162 = 2W

81 = W

the width of the field is 81 yards.

hope this helped!

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Given the following geometric sequence, find the common ratio:<br><br> {225, 45, 9...}
Tom [10]

Answer:

\frac{1}{5}  is the common ratio

Step-by-step explanation:

Common ratio(r) states that the ratio of each term of a geometric sequence to the term preceding it.

r = \frac{a_2}{a_1} =\frac{a_3}{a_2}........\frac{a_{n+1}}{a_n}

Given the sequence:

225, 45, 9, .........

Here,

a_1 = 225

a_2 = 45

a_3 = 9 and so on...

Using definition to find r.

r = \frac{45}{225}=\frac{9}{45}......

After solving we get;

r = \frac{1}{5}

Therefore, the common ratio is, \frac{1}{5}

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3 years ago
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Given f(x) = 3x^3 - 4x^2 + x - 1 , what is f(2) ?
Yakvenalex [24]
2 will replace each x on the right

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7 0
3 years ago
Debbie buys a tree for the holidays. She would like to determine the amount of space it will take up in her living room. The tre
Rina8888 [55]

Answer:

Volume = 200.96 cubic feet

Step-by-step explanation:

Volume of a cone is given by the formula   V=\frac{1}{3}\pi r^2 h

Where r is the radius and h is the height

Given r = 4 and height is 3 times that. So height is 4*3 = 12

Plugging these into the formula we get:

Volume of Cone =  \frac{1}{3}\pi (4)^2 (12)\\=\frac{1}{3}(3.14)(16)(12)\\=200.96

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3 0
3 years ago
Suppose a company produces report indicates that the surveyed distance between two points is 1200 feet with a margin of error of
Otrada [13]
<h2>Hello!</h2>

The answers are:

MaximumDistance=1200.1ft\\MinimumDistance=1199.9ft

<h2>Why?</h2>

Since we are given the margin of error and it's equal to ±0.1 feet, and we know the surveyed distance, we can calculate the maximum and minimum distance. We must remember that margin of errors usually involves and maximum and minimum margin of a measure, and it means that the real measure will not be greater or less than the values located at the margins.

We know that the surveyed distance is 1200 feet with a margin of error of ±0.1 feet, so, we can calculate the maximum and minimum distances that the reader could assume in the following way:

MaximumDistance=ActualDistance+0.1feet\\\\MaximumDistance=1200feet+0.1feet=1200.1feet

MinimumDistance=ActualDistance-0.1feet\\\\MaximumDistance=1200feet-0.1feet=1199.9feet

Have a nice day!

4 0
3 years ago
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