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44a³ and 4a
Let us do the numbers and variables separately
44 and 4 are both multiples of each other
Therefore, the GCF is 4
a³ and a, a will be the GCF since a³ is not present on both
Finally, 4a will be the GCF
Answer:
196 cm²-153.9375 cm² = 42.0625 cm ²
Step-by-step explanation:
First, solve for the whole 14^2 = 196 cm²
Now, we know it's lenths are the same so it's a square.
Lastly we need to deduct the quarter circle in the square. Use Formula A=πr² = A≈615.75 cm² /4 = 153.9375 cm²
Step-by-step explanation:
Firstly, we'll try to simplify the integrand. By hint 1, we see that:

Simplifying the integrand gives us:

Next, by hint 2, we observe that:

So this tells us to make the substitution: 
Doing so gives us:
, which should be trivial.
AnsweIt should be right
Step-by-step explanation:
Answer: 687
Step-by-step explanation:
normally distributed
μ = 498
σ = 108
Top 4%
P(X > a) = 0.04
P(Z > a-498/108) = 0.04
Using the table attached, for the top 4%:
0.50 - 0.04 = 0.46
a-498/108 = 1.75
a-498 = 189
a = 687
The minimum score for the scholarship is 687.