Question

You order fifteen burritos to go from a Mexican restaurant, six with hot peppers and nine without. However, the restaurant forgot to label them. If you pick three burritos at random, find the probability of the given event. (Round your answer to three decimal places.)
At most two have hot peppers.

Answer 1

Answer: 0.936

Step-by-step explanation:

Given : Total burritos ordered  = 15

Number of burritos with hot peppers = 6

number of burritos without hot peppers =9

Then , the proportion of burritos with hot peppers= $p=\dfrac{6}{15}=0.4$

The number of burritos picked: n = 3

Then using binomial probability , the probability that at most two have hot peppers is given  by:-

$P(x\leq2)=1-P(x=3)\\\\=1-^3C_3(0.4)^3(0.6)^0\\\\=1-(1)(0.4)^3=0.936$

Hence, the required probability = 0.936