10)
60in=60in × (1ft/12in) = 5ft
30in= 30in × (1ft/12in) = 2.5ft
12in = 12in × (1ft/12in) = 1ft
answer is = 5ft × 2.5ft× 1ft =12.5 ft^3 = a
11)
dozen = 12 hammers
12 hammers = 20 pounds
therefore 1 hammer= 20/12 = 1.6666 lb
21 hammers ×1.666 = 35 = c
12)
convert qt to gal
600 gal × 4 qt/gal = 2400 qt
2400 qt ÷ 120 qt/min
=20 min = d
13)
Carla is 12
rob is 12+5= 17
cousin is 12-7 = 5
12+17+5= 34 =a
15)
convert 60ft into yards
60 ft × 0.333 yd/ft =20 yd
diameter = 20 yd
area of circle = (pi/4)×d^2
(pi/4)×20^2= 314.16 = b
Answer = 55,25 inches
Solution -
let's take x as length and y as width of the metal piece. As per the question x is 30 more than y,
⇒ x = y + 30
Then four square pieces of side 6 are cut from each corner,
so the new length and width are
x-12 , y-12
Then the volume of the new box created will be
(x-12)(y-12)6
in the question the volume of the given figure is given to be 3354
so (x-12)(y-12)6 = 3354
putting the value of x in the the above equation
⇒ (y+30 - 12)(x-12) = 3354/6 = 559
⇒ (y+18)(y-12) = 559
⇒ y² + 6y - 775 = 0
⇒ y² + 31y - 25y -775 = 0
⇒ (y+31)(y-25) = 0
⇒ y = -31, 25
as length can not be -ve , so y = 25
then x = 25+30 = 55
Hence the dimensions of the metal piece are 55, 25 inches
If you zoomed in i could've helped more. Bummer...
One possible outfit is available because 1 pair of pants and 1 shirt is one outfit
Answer:
76.25°
Step-by-step explanation:
The solution to the differential equation is an exponential curve with a horizontal asymptote at Tm. It passes through (0, 145) and (30, 95), so the equation can be written as ...
T = 80 +65((95-65)/(145-65))^(t/30)
T = 80 +65(3/8)^(t/30)
That is, the temperature difference is reduced to 3/8 of its original value in 30 minutes.
Since the coffee in cup B cools twice as fast, it will cool to the same temperature (95°) in 15 minutes. In the next 15 minutes, the temperature difference will be reduced to (3/8)^2 of the original 80°, so will be 11.25°. That is, the temperature of cup B will be ...
11.25° +65° = 76.25°
after 30 minutes.