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3 years ago

The perimeter of a rectangle is 142m. The length is 2m more than twice the width. Find the dimensions.

1 answer:

7 0

Equation:
(2w+2) + w + (2w+2) + w

Combine Like Terms:
6w+4=142 m (since that's our perimeter)

Subtract 4 from both sides:
6w=138

Divide 6 from both sides
w=23

To find the length... Plug in our width into our "length" equation
(2(23)+2)
46+2
l=48

Final Answer:
w=23
l=48

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4 years ago

Two equations are given below

natulia [17]

Answer:

(-5,-3)

Step-by-step explanation:

In this case to find the solution you could use substitution. This way you can solve without changing the equation over again.

(b - 2) - 3b = 4

b - 2 - 3b = 4

-2b - 2 = 4

-2b = 6

b = -3

Plug back in to find value a

a = (-3) - 2

a = -5

Check your answer before submitting

(-5) - 3(-3) = 4

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Hope this helps

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4 years ago

Write the equations for all vertical horizontal asymptotes. Vertical asymptote(s):Horizontal asymptote(s):Find all x-intercepts

NISA [10]

We have the next graph

And we must find:

1. Vertical asymptote(s):

We can see that there is a vertical asymptote when x = 2.

So, the vertical asymptote is

$x=2$

2. Horizontal asymptote(s):

We can see that there is a horizontal asymptote y = -1

So, the horizontal aymptote is

$y=-1$

3. x-intercept(s) and y-intercept(s):

We can see the graph intercepts the x-axis when x = -6

So, the x-intercept is (-6, 0)

We can see the graph intercepts the y-axis when y = 3

So, the y-intercept is (0, 3)

4. Domain nd Range:

Domain: The domain is the set of numbers that we can take in x-axis for the function.

Since we have a vertical asymptote that is x = 2 and we don´t have any more vertical asymptote the domain will be all real numbers except the value of the asymptote. So, the domain is