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BabaBlast [244]
3 years ago
14

For a school fundraiser, Mai will make school spirit bracelets. She will order bead wiring and alphabet beads to create the scho

ol name on the bracelets. Mai must spend $250 on wire and $5.30 per bracelet for beads.
Complete the table giving the total cost Mai will spend to make each specific number of bracelets.
number of bracelets cost in dollars
20
40
60
Write an expression for the cost of making LaTeX: nn bracelets.
What is the maximum number of bracelets Mai can make with a budget of $1,500?
Mathematics
1 answer:
Ket [755]3 years ago
8 0

Answer: Total number of bracelet: 235

Step-by-step explanation:

Given:

Total budget= $1,500

Spend on wire = $250

Per braclet beads = $5.30

Find:

Total number of bracelet

Computation:

Total number of bracelet = [1,500 - 250]

Total number of bracelet = [1,250/ 5.30

Total number of bracelet = 235.849

Total number of bracelet = 235 [By round minium]

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A plane left 30 minutes late than its schedule time and in order to reach the destination 1500 km away in time it had to increas
schepotkina [342]
Let x= the usual speed
1500/x would equal how long it usually took the plane to read the destination
1500/(x+100) would equal how long it would take the plane now
So\frac{1500}{x} - \frac{1500}{x+100} =  \frac{1}{2} because it would lose 30 minutes already
Simplify:
\frac{1500(x+100)-1500x}{x(x+100)} =  \frac{1}{2}
\frac{1500x+150000-1500x}{x^2+100x} = \frac{1}{2}
\frac{150000}{x^2+100x} = \frac{1}{2}
\frac{300000}{x^2+100x} =1
300000= x^{2} +100x

x^2+100x-300000=0

x^2+600x-500x-300000=0

x(x+600)-500(x+600)

(x-500)(x+600)

x=500, x \neq -600


The usual speed was 500 hm/hr

7 0
3 years ago
Suppose A and B are square matrices of the same size. Which of the following are necessarily true?
kiruha [24]

Answer:

c. (A + B)^2-A^2 + 2AB + B^2

Step-by-step explanation:

Given that:

a.

(A-B)^2 = A^2 - 2AB + B^2

If and only if AB = BA

Then;

(A-B)^2 = (A -B ) (A - B)

(A-B)^2 = A^2 - AB-BA + B^2    (FALSE)

b.

(AB)^2=A^2B^2

on true if any only if AB =BA

(AB)^2= (AB) (AB)

c.

(A+ B)^2 =  A^2 + 2AB + B^2

(A+ B)^2 = (A + B) (A+B)

(A+ B)² = A × A + A × B + B × A + B × B

(A+ B)^2 = A^2 + A*B + B*A + B^2

This is true

5 0
3 years ago
Can someone help me please
svet-max [94.6K]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Translation 12 units down puts each point 12 units lower on the graph than the position where it is currently shown. Segment RS is now shown on the line y=9. It will be translated straight down so it appears on the line y = 9-12 = -3.

Similarly, T has a y-coordinate of 2. Translated down 12, it will have a y-coordinate of y = 2-12 = -10.

The x-coordinates of all of the points remain the same.

The translation is shown in the attachment.

3 0
3 years ago
FIND THE TOTAL NUMBER OF COMBINATIONS
sleet_krkn [62]

Answer:

B.120 i took the test and got it right.

8 0
3 years ago
Read 2 more answers
A movie theater has a seating capacity of 235. The theater charges $5 for children, $7 for students, and $12 for adults. There a
Annette [7]

Answer:

61 adults, 122 children, and 52 students

Step-by-step explanation:

Let a = amount of adults, c = amount of children, and s = amount of students.

Let's go over what we know:

total amount: 235

twice as many children as adults

children: $5

student: $7

adult: $12

Using this information, we can determine the following:

a = 1/2c

235 = c + s + a

1706 = 5c + 7s + 12a

Since we know a = 1/2c, plug 1/2c in for a. The equations become:

235 = c + s + 1/2c

1706 = 5c + 7s + 6c

Now, solve the inequalities by substitution.

235 = c + s + 1/2c

235 = 1 1/2c + s

-s + 235 = 1 1/2c

-s = -235 + 1 1/2c

s = 235 - 1 1/2c

Now, plug in the value for s into the other equation.

1706 = 5c + 7(235 - 1 1/2c) + 6c

-5c + 1706 =  7(235 - 1 1/2c) + 6c

-5c = -1706 + 7(235 - 1 1/2c) + 6c

-5c = -1706 + 1645 - 21c/2 + 6c

-5c = -61 - 21c/2 + 6c

-5c = -61 - 9c/2

c = 122

Now, plug in the value for c into the value of s.

s = 235 - 1 1/2(122)

s = 235 - 183

s = 52

Finally, plug in the value for c into the value of a.

a = 1/2(122)

a = 61

To check, add up all values to make sure they equal 235.

61 + 52 + 122 = 235.

Therefore, the final answers are 61 adults, 122 children, and 52 students.

7 0
3 years ago
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