Answer:
The main method should simply terminate if the FileNotFoundException occurs.
Explanation:
Considering the full code snippet
snippet:public static void main(String[] args) throws FileNotFoundException
public static void main(String[])
represent the entry point method to a java main method
The addition of
throws FileNotFoundException
widens the scope of the main method to explicitly specifies that an exception named the FileNotFoundException may be thrown.
So, if any part of the code explicitly throws the FileNotFoundException the compiler makes use of this to throw an exception.
By throwing an exception, the main method is not catching any exceptions, instead it handles the FileNotFoundException by throwing it to the source which invoked the main method
This is required by the compiler to terminate the program if the FileNotFoundException occurs.
Answer:
thick
Explanation:
i took the test and got it right
Answer:
The solution code is written in Java
- public static void checkCommonValues(int arr1[], int arr2[]){
- if(arr1.length < arr2.length){
- for(int i = 0; i < arr1.length; i++){
- for(int j = 0; j < arr2.length; j++){
- if(arr1[i] == arr2[j]){
- System.out.print(arr1[i] + " ");
- }
- }
- }
- }
- else{
- for(int i = 0; i < arr2.length; i++){
- for(int j = 0; j < arr1.length; j++){
- if(arr2[i] == arr1[j]){
- System.out.print(arr2[i] + " ");
- }
- }
- }
- }
- }
Explanation:
The key idea of this method is to repeated get a value from the shorter array to check against the all the values from a longer array. If any comparison result in True, the program shall display the integer.
Based on this idea, an if-else condition is defined (Line 2). Outer loop will traverse through the shorter array (Line 3, 12) and the inner loop will traverse the longer array (Line 4, 13). Within the inner loop, there is another if condition to check if the current value is equal to any value in the longer array, if so, print the common value (Line 5-7, 14-16).
B. South America
[ignore:20 CHARACTERS]
Answer:
def scramble(s):
if len(s) % 2 == 1:
index = int(len(s)//2)
else:
index = int(len(s)/2)
return s[index:] + s[:index]
Explanation:
Create a function called scramble that takes one parameter, s
Check the length of the s using len function. If the length is odd, set the index as the floor of the length/2. Otherwise, set the index as length/2. Use index value to slice the s as two halves
Return the second half of the s and the second half of the s using slice notation (s[index:] represents the characters from half of the s to the end, s[:index] represents the characters from begining to the half of the s)