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Semenov [28]
3 years ago
12

In symmetric key cryptosystem, assume that Alice and Bob have set up a common key Kab. This key is only known to Alice and Bob.

(1a) Can we achieve data origin authentication?
Computers and Technology
1 answer:
azamat3 years ago
4 0

Answer:

yes

Explanation:

If it is guranteed the key is only known to Alice and Bob and there is no risk of man in the middle attack or channel spoofing so we can achieve data origin authentication

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Programs for embedded devices are often written in assembly language. Some embedded processors have limited instructions, like M
oksano4ka [1.4K]

Answer:

#include <iostream>

using namespace std;

int main()

{

   char address[2];

   int tag, firstBit, secondBit, setNumber;

   int cache[4][2]={{1,5}, {2,4}, {3,2}, {6,0}};

   cout << "Enter the address as hex(in small letters: "<

   cin >> address;

   for (int i < 0; i < 8; i++){

       if (address[0] == '0'){

           tag = 0;

           firstBit = 0;

        } else if (address[0] == '1'){

           tag = 0;

           firstBit = 1;

        } else if (address[0] == '2'){

           tag =1;

           firstBit = 0;

        } else if (address[0] == '3'){

           tag = 1;

           firstBit = 1;

        } else if (address[0] == '4'){

           tag = 2;

           firstBit = 0;

        } else if (address[0] == '5'){

           tag = 2;

           firstBit = 1;

        }  else if (address[0] == '6'){

           tag = 3;

           firstBit = 0;

       } else if (address[0] == '7'){

           tag = 3;

           firstBit = 1;

       }  else if (address[0] == '8'){

           tag = 4;

           firstBit = 0;

       } else if (address[0] == '9'){

           tag = 4;

           firstBit = 1;

       }   else if (address[0] == 'A'){

           tag = 5;

           firstBit = 0;

       } else if (address[0] == 'B'){

           tag = 5;

           firstBit = 1;

       }  else if (address[0] == 'C'){

           tag = 6;

           firstBit = 0;

       } else if (address[0] == 'D'){

           tag = 6;

           firstBit = 1;

        }  else if (address[0] == 'E'){

           tag = 7;

           firstBit = 0;

       } else if (address[0] == 'F'){

           tag = 7;

           firstBit = 1;

       } else{

           cout<<"The Hex number is not valid"<< endl;

        }

   }

   if(address[1]>='0' && address[1]<'8'){

       secondBit = 0;

  }  else if(address[1]=='8'|| address[1]=='9'||(address[1]>='a' && address[1]<='f')){

       secondBit = 1;

   }  else{

       cout<<"The Hex number is not valid"<< endl;  

       return 0;

   }

   setNumber = firstBit * 2 + secondBit;

   if(cache[setNumber][0]==tag || cache[setNumber][1]==tag){

       cout<<"There is a hit";

   } else{

       cout<< "There is a miss";

   }

   return 0;

}

Explanation:

The C++ source code prompts the user for an input for the address variable, then the nested if statement is used to assign the value of the firstBit value given the value in the first index in the address character array. Another if statement is used to assign the value for the secondBit and then the setNumber is calculated.

If the setNumber is equal to the tag bit, Then the hit message is printed but a miss message is printed if not.

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Observe the things at Home in which you are using binary
vazorg [7]

Explanation:

All five things i can come up with her

1. Doors (we either open or close them)

2. Tap (we either open or close the valve)

3.  Electric stove/cooker

4. The lid of containers

5. Shoes/ foot wears(we put them ON or OFF)

7 0
3 years ago
G The method of mapping where each memory locationis mapped to exactly one location in the cache is
Otrada [13]

Answer:

Direct Mapped Cache

Explanation:

Given that a Direct Mapped Cache is a form of mapping whereby each main memory address is mapped into precisely one cache block.

It is considered cheaper compared to the associative method of cache mapping, and it is faster when searching through it. This is because it utilizes a tag field only.

Hence, The method of mapping where each memory location is mapped to exactly one location in the cache is "Direct Mapped Cache"

4 0
3 years ago
Organizations should communicate with system users throughout the development of the security program, letting them know that ch
Fed [463]

Answer:

Yes it is true.The organization should indeed communicate with a system user throughout the development of a security program. A corporation needs a security policy that must be developed by management at all levels, including organization and employees at the operational level. For a corporate security plan, it is essential to reduce the resistance of the expected changes and define the objective.

Explanation:

Three objectives of the security plan in an organization are:

  • Identify the sensitive system and plan
  • Create and define the strategy and control of the system.
  • Develop and implement the training programs.

Security Information is one of the essential factors in the organization.For an organization, the information should be protected.

7 0
3 years ago
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