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ale4655 [162]
3 years ago
9

The vertices of the hyperbola are (+3,0) (2.0) 010, +3)

Mathematics
1 answer:
Whitepunk [10]3 years ago
3 0

Answer:15

Step-by-step explanation:

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Hello I hope you having a good day what is 163 dived by 859
aleksley [76]

Answer:

Exact Form:

163 /859

Decimal Form:

0.18975552 969

Step-by-step explanation:

Reduce the expression, if possible, by cancelling the common factors.

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Find the equation of the line that passes through A and B
Alex777 [14]

Answer:

First we need to find the slope. This is (7 - 3) / (4 - 2) = 2. Since we know the slope, we can use point-slope form. I'm using the point (2, 3).

y - 3 = 2(x - 2)

y - 3 = 2x - 4

y = 2x - 1

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How to prove all pairs of corresponding sides and angles are congruent
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3 years ago
if 1 mile is 5280 feet, and it is 2 miles from Ellie's house to the school, about how many feet is it from ellie's house to the
Bess [88]
This is a conversion problem. We know that 1 mile is 5280 feet, right? Since Ellie lives 2 miles, and two is double of 1, we just take 5280 and multiply that by two (or add it twice) to find how many feet is between Ellie's house and school. 5280 x 2 = 10560 (you get the same answer if you add 5280 twice). Therefore, 10560 feet lies between Ellie's house and school.
6 0
3 years ago
Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.
WINSTONCH [101]

Answer:

a) y(t) = y_{0}e^{4t} + 2. It does not have a steady state

b) y(t) = y_{0}e^{-4t} + 2. It has a steady state.

Step-by-step explanation:

a) y' -4y = -8

The first step is finding y_{n}(t). So:

y' - 4y = 0

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

r - 4 = 0

r = 4

So:

y_{n}(t) = y_{0}e^{4t}

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

y_{p}(t) = C

So

(y_{p})' -4(y_{p}) = -8

(C)' - 4C = -8

C is a constant, so (C)' = 0.

-4C = -8

4C = 8

C = 2

The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

y(t) = y_{0}e^{4t} + 2

b) y' +4y = 8

The first step is finding y_{n}(t). So:

y' + 4y = 0

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

r + 4 =

r = -4

So:

y_{n}(t) = y_{0}e^{-4t}

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

y_{p}(t) = C

So

(y_{p})' +4(y_{p}) = 8

(C)' + 4C = 8

C is a constant, so (C)' = 0.

4C = 8

C = 2

The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

y(t) = y_{0}e^{-4t} + 2

6 0
3 years ago
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