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4 years ago

PLZ HELP I BEG DUE IN 30 MIN!!! 30 POINTS!!!!

Mathematics

2 answers:

Nezavi [6.7K]4 years ago

7 0

Answer:

A to B is 5 ( -3 to 2 = 5).//!!//Then you are gonna be Using the ratio 1/5, split the distance in to 1/5th's, point K would be at -2.

katrin [286]4 years ago

6 0

The total distance from A to B is 5 ( -3 to 2 = 5).

Using the ratio 1/5, split the distance in to 1/5th's, point K would be at -2.

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The amusement park’s rules state that all seats in a car must be filled before the ride begins. Does this group of 40 students h

Lunna [17]

Answer:

Fart

Step-by-step explanation:

pull down your pants and fart in you siblings face

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3 years ago

Use the graph to answer the question.

leonid [27]

Answer: A translation and a reflection

Step-by-step explanation:

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3 years ago

Read 2 more answers

suppose the depth of the tide in a certain harbor can be modeled by y = 20 + 5 cos (pi/6 t), where y is the water depth in feet

Rom4ik [11]

Answer:

- high tide occurs at 12 noon and 12 midnight

- Low tide occurs at 6 a.m and 6 p.m

- maximum depth value = 20 ft

- Minimum depth value = 15 ft

Step-by-step explanation:

The depth is modelled as;

y = 20 + 5 cos (πt/6)

We are told that t = 0 represents 12:00 midnight.

This is high tide because at t = 0, the cos function will be at it's maximum value of 1 since cos 0 = 1.

Max depth value is;

y = 20 + 5(0)

y = 20 ft

Minimum depth value will be the low tide and it will be when the cos function is equal to -1.

Thus;

y = 20 + 5(-1)

y = 15 ft

Since t represents number of hours and since at 12 midnight, t = 0, thus; high tide will occur again at;

12 noon

Also, let's check for low tide.

Let's try t = 6 which means 6 a.m

Thus;

y = 20 + 5 cos (π(6)/6)

y = 20 + 5 cos π

Cos π has a value of -1

Thus;

y = 20 + 5(-1)

y = 20 - 5

y = 15 ft

Thus;

Low tide occurs at 6 a.m and 6 p.m

5 0

4 years ago

The Acculturation Rating Scale for Mexican Americans (ARSMA) is a psychological testdeveloped to measure the degree of Mexican/S

maria [59]

Answer:

95% confidence interval for the mean ARSMA score for first-generation Mexican Americans

(2.13264 , 2.58736)

Step-by-step explanation:

Step(i):-

Mean of the Population = 3.0

Standard deviation of the Population = 0.8

Given Mean of the sample(x⁻ ) = 2.36

Standard deviation of the sample (S) = 0.8

size of the sample = 50

Level of significance =0.05

Degrees of freedom = n-1 = 50-1 = 49

$t_{\frac{0.05}{2} , 49} = 2.0096$

Step(ii):-

95% confidence interval for the mean ARSMA score for first-generation Mexican Americans

$(x^{-} - t_{(\frac{\alpha }{2},df )} \frac{S}{\sqrt{n} } , (x^{-} +t_{(\frac{\alpha }{2},df )} \frac{S}{\sqrt{n} })$

$(2.36 - 2.0096 \frac{0.8}{\sqrt{50} } , 2.36 +2.0096\frac{0.8}{\sqrt{50} })$

( 2.36 - 0.22736 , 2.36 + 0.22736)

(2.13264 , 2.58736)

Final answer:-

95% confidence interval for the mean ARSMA score for first-generation Mexican Americans

(2.13264 , 2.58736)

7 0

3 years ago

How do I describe the real zeroes of this function using Descartes's Rule of Signs?

Serhud [2]

The number of positive roots is the number of changes of signs there are, then decrease by 2 each time and stop when you get to 1 or 0

negative roots, sub every x with -x and reevaluate, count change of signs
decrease by 2 each time and stop when you get to 1 or 0

y=+2x⁵-x⁴-2x³+4x²+x-2
+,-,-,+,+,-
1 2 3

3 or 1 positive roots

replace x with -x ( baically flip all signs of odd powerd numbers)

y=-2x⁵-x⁴+2x³+4x²-x-2
-,-,+,+,-,-
1 2

2 or 0 negative roots

3 or 1 positive roots
2 or 0 negative roots
2nd option is answer

4 0

4 years ago