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Fiesta28 [93]
3 years ago
12

Imagine you conducted a study to look at the association between whether an expectant mother eats breakfast (or not) and the gen

der of her baby. Cramér's V = .22. How would you interpret this value? (Hint: Cramér's V can range between 0 and 1.) There was a small to medium association between baby gender and whether the mother ate breakfast every day. 22% of the variation in frequency counts of baby gender (boy or girl) can be explained by whether or not the mother ate breakfast every day. 2.2% of the variation in frequency counts of baby gender (boy or girl) can be explained by whether or not the mother ate breakfast every day. There is a medium to large association between the gender of the baby and whether or not the mother ate breakfast every day.
Mathematics
1 answer:
mario62 [17]3 years ago
3 0

Answer:

: The percentage of newborn infants who are exclusively breastfed at the time of hospital discharge.

Data Source: Rhode Island Department of Health, Center for Health and Data Analysis, Newborn Developmental Risk Screening Program Database and Maternal and Child Health Database.

Footnotes: The year indicated is the mid-year of a five-year period of data.

Step-by-step explanation:

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kim just went to the store and bought 2 presents that cost kim $1,800 and her Taxes or 88 cents how much does kimmlin have to pa
strojnjashka [21]
3384 because .88 times 1800 is 1584 and you have to add that to 1800 making it 3384 (or the questions is really easy and its just 1800.88)
6 0
3 years ago
↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓<br> No Words <br> Part 1
MissTica
3m + 2n= p solve for n

subtract 3m on both sides
2n = p - 3m

divide both sides by 2
n = p/2 - 3m/2
-----------------------

xy - 5 = k solve for x
add 5 on both sides
xy = k + 5

divide both sides by y
x = k/y - 5/y
3 0
3 years ago
Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?
Yanka [14]

Answer:

Step-by-step explanation:

\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.

\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\

(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+  \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.

8 0
1 year ago
Glenna says that the height of her house is 1 yard is her claim reasonable
muminat
No, her answer is not reasonable because one yard is equal to 3 feet.
4 0
3 years ago
Read 2 more answers
A hotel offers a reward program based on the number of night stayed. The function f(x) represents the number of free nights earn
iris [78.8K]

Answer:

a. A customer earns 1 free night per 10 nights stayed.  

Step-by-step explanation:

The missing function is:

f(x) = x/10  

The missing options are:

<em> a. A customer earns 1 free night per 10 nights stayed.  </em>

<em> b. A customer starts with 1 free night and then earns another free night after every 10 nights stayed. </em>

<em> c.A customer earns x – 10 free nights for every 10 nights stayed.  </em>

<em> d. A customer earns 10 free nights after x number of nights stayed. </em>

The function means that after a customer stayed 10 nights, a free night is earned. That is, replacing x = 10 into the function, we get:

f(10) = 10/10  = 1

which means 10 nights are equivalent to 1 free night.

7 0
3 years ago
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