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3 years ago

Help me plz I need help

Mathematics

2 answers:

Oksi-84 [34.3K]3 years ago

6 0

C. is the correct answer because (x+3)^2 is x^2+6x+9

Leviafan [203]3 years ago

4 0

Hope this helps!! Good luck

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What are all the pairs of twin primes between 25 and 55?

Oksana_A [137]

So twin primes are prime numbers that have a difference of 2. The ones between 25 and 55 are (29,31) and(41,43). Hope that helps

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2 years ago

Find the measure of

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2 years ago

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nikdorinn [45]

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2 years ago

Solve for x rounding to the nearest hundredth will give to brainlest!!!

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2 years ago

Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers

Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the $x^2$ coefficient is 1, i.e. the equation is written like $x^2+bx+c=0$ , then you can say the following about the coefficients b and c:

$b$ is the opposite of the sum of the roots
$c$ is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

$4+(-2) = 4-2 = 2 \implies b = -2$
$4 \cdot (-2) = -8 \implies c = -8$

So, the equation is $x^2-2x-8=0$

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

$\dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}$
$\dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}$

And so the equation is

$x^2 - \dfrac{5}{4} + \dfrac{3}{8} = 0$

In order to have integer coefficients, you can multiply both sides of the equation by 8:

$8x^2 - 10 + 3 = 0$

5 0

2 years ago