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4 years ago

Find the volume of a pyramid 5 yards tall if the base is a rectangle 15 feet by 6 feet.

Mathematics

2 answers:

Contact [7]4 years ago

5 0

If i am right is V=150

BaLLatris [955]4 years ago

3 0

V=lwh/3=5*15*6/3=160

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The sum of a number times 6 and 5 equals 4 translate the sentence into an equation

yan [13]

If x is the number we get:-

6x + 5 = 4

3 0

3 years ago

Brandon picked 14 of a pound of cherries. That afternoon, Brandon's brother ate 12 of the cherries. How many pounds of cherries

stellarik [79]

Answer:

Step-by-step explanation:

Brandon picked 14 pounds of cherries but later in the afternoon Brandon's brother ate 12 so you would subtracts

14-12 = 2

8 0

3 years ago

The measurements 45.367 cm and 43.43 cm are made in the same unit of measure. Which measurement is less precise? Explain your an

Kaylis [27]

Answer:

45.367 cm

Step-by-step explanation:

Approximating to a more number of decimal places gives a better estimation of the exact value.

For 45.367 cm, we approximated to three decimal places or five significant figures.

For 43.43 cm, the approximation is done to four decimal places.

Therefore the measurement 45.367cm is more precise because it has a relatively smaller error.

7 0

4 years ago

There are 14 juniors and 16 seniors in a chess club. a) From the 30 members, how many ways are there to arrange 5 members of the

Dmitrij [34]

Answer:

a) 17,100,720

b) 4,717,440

c) 10,920

d) 2821

Step-by-step explanation:

14 juniors and 16 seniors = 30 people

a) From the 30 members, how many ways are there to arrange 5 members of the club in a line?

As it is a ordered arrangement

30.29.28.27.26 = 17,100,720

b) How many ways are there to arrange 5 members of the club in a line if there must be a senior at the beginning of the line and at the end of the line?

16.28.27.26.15 = 4,717,440

c) If the club sends 2 juniors and 2 seniors to the tournament, how many possible groupings are there?

Not ordered arrangement. And means that we need to multiply the results.

C₁₄,₂ * C₁₆,₂

C₁₄,₂ = 14.13.12! = 14.13 = 91

12! 2! 2

C₁₆,₂ = 16.15.14! = 16.15 = 120

14! 2! 2

C₁₄,₂ * C₁₆,₂ = 91.120 = 10,920

d) If the club sends either 4 juniors or 4 seniors, how many possible groupings are there?

Or means that we need to sum the results.

C₁₄,₄ + C₁₆,₄

C₁₄,₄ = 14.13.12.11.10! = 14.13.12.11 = 1001

10! 4! 4.3.2.1

C₁₆,₄ = 16.15.14.13.12! = 16.15.14.13 = 1820

12! 4! 4.3.2.1

C₁₄,₄ + C₁₆,₄ = 1001 + 1820 = 2821

7 0

3 years ago

If x varies inversely as y and x=12 when y=9, find x when y=54

beks73 [17]

Answer:

x = 72

Step-by-step explanation:

We set the two equal to each other

x = 12/y = 9 is equal to x/y = 54.

In order for 9 to get to 54, you have to multiply it by 6. Since you multiplied the denominator with 6, you have to do the same with the numerator. 12 times 6 is 72.

x = 72

3 0

3 years ago