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madreJ [45]
3 years ago
11

Quadratic function whose zeros are 8 and 3?

Mathematics
1 answer:
arlik [135]3 years ago
7 0

Answer:

The required quadratic function is

\therefore f(x)=x^{2} -11x+24

Step-by-step explanation:

Given:

Let α and β be the zeros of the quadratic function.

∴ α = 8 and

∴ β = 3

To Find :

Quadratic function.

i.e f(x) =?

Solution:

he quadratic function in x when Alpha ( α ) and beta ( β ) are the zeros given by

f(x) = x^{2} -(\alpha+\beta ) x +\alpha\times \beta\\\textrm{Substituting alpha and beta we get}\\= x^{2} -(8+3)x + 8\times 3\\\\\therefore f(x)=x^{2} -11x+24

\therefore f(x)=x^{2} -11x+24

Which is the required quadratic function

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2/3y+1=1/6y+8 equals what
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