What is the answer to (X+3)(-x-2)=y

If the original square had a side length of

irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas in the attached figure N 3, and the trinomial is $x^{2} +11x+28$

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

$Length=(x+4)\ in$

$width=(x+7)\ in$

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

$A1=(x)(x)=x^{2}\ in^2$

$A2=(4)(x)=4x\ in^2$

$A3=(x)(7)=7x\ in^2$

$A4=(4)(7)=28\ in^2$

The total area of the second rectangle is the sum of the four areas

$A=A1+A2+A3+A4$

State the product of (x+4) and (x+7) as a trinomial

$(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28$

Part c) If the original square had a side length of x = 2 inches, then what is the area of the second rectangle?

we know that

The area of the second rectangle is equal to

$A=A1+A2+A3+A4$

For x=2 in

substitute the value of x in the area of each portion

$A1=(2)(2)=4\ in^2$

$A2=(4)(2)=8\ in^2$

$A3=(2)(7)=14\ in^2$

$A4=(4)(7)=28\ in^2$

$A=4+8+14+28$

$A=54\ in^2$

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

$A(x)=x^{2} +11x+28$

For x=2 in

substitute and solve for A(x)

$A(2)=2^{2} +11(2)+28$

$A(2)=4 +22+28$

$A(2)=54\ in^2$ ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0

3 years ago

Find the midpoint of the segment with the given endpoints. M(–2, 1) and N(–3, 2)

mafiozo [28]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
M(\stackrel{x_1}{-2}~,~\stackrel{y_1}{1})\qquad 
N(\stackrel{x_2}{-3}~,~\stackrel{y_2}{2})
\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{-3-2}{2}~~,~~\cfrac{2+1}{2} \right)\implies \left(-\frac{5}{2}~,~\frac{3}{2} \right)$

5 0

3 years ago

Read 2 more answers

What is the product written in scientific notation?

wel

Answer is C. Definitely not d right off the bat because both exponents are negative so cross that out. After that its just counting zeros.

5 0

3 years ago

Read 2 more answers

Work out (9×10²)+(7×10³) State your answer in standard form

Sunny_sXe [5.5K]

Answer:

(9×10×10)+(7×10×10)

900+700

1600

1.6×10^3

4 0

3 years ago

Really need help please

Anettt [7]

I am too lazy I'll explain so you find 688 minus 267 then you divide the difference by 6 and then u subtract the difference from 267x100 because that will be the total. Then u find the mean of the 94 numbers u get!

3 0

3 years ago