(1.8 * 10^2) * (5 * 10^2)

How are you supposed to find the slope of a line?

MArishka [77]

You have to find two definite points on the graph, i'll use (1,4) and (2,6) as an example

The slope formula is (y2-y1)/(x2-x1)

This means you have to subtract the first y value from the second divide it by the first x value subtracted from the second

In my example you have to do (6-4)/(2-1) to get 2/1, or 2

Hope this helps!

7 0

3 years ago

Question 1 (3 points) What value of p makes this equation true? 3p - 8 = -23 . O p = -6 Op = -5 Op = 5 p = 6

olchik [2.2K]

The value of p that makes the given equation true is equal to: B. p = -5

<u>Given the following equation:</u>

$3p - 8 = -23$

To find a value of p that makes the given equation true:

In this exercise, you're required to determine a value of p that satisfies the given equation true such that when substituted into the equation, it has a true result or outcome.

Rearranging the equation by collecting like terms, we have:

$3p - 8 = -23\\\\3p=-23+8\\\\3p=-15\\\\p=\frac{-15}{3}$

p = -5

Find more information: brainly.com/question/3600420

7 0

2 years ago

Whats the area of a circle with a circumference of 31.4unit

marin [14]

Answer:

78.54

Step-by-step explanation:

first you have to divided 31.4 by 3.14 to get your diameter so you can get your radius. 31.4 divided by 3.14 equals 10 and 10 divided by 2 equals 5 which is you radius. The formula for area for a circle is πr². 5 squared is 25 and 3.14 times 25 equals 78 .54 which is your answer.

8 1

3 years ago

A projectile is launched from the ground at an angle of theta above the horizontal with an initial speed of v in ft/s. The rang

VARVARA [1.3K]

Answer:

$\theta=24.4^\circ$

Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range of a projectile is in reality approximated by the equation $x=\frac{v^2}{g} sin(2\theta)=\frac{v^2}{32ft/s^2} sin(2\theta)$ , where we will use ft for distances.

From the given equation we have then $\frac{x32ft/s^2}{v^2} =sin(2\theta)$ , which means $\theta=\frac{Arcsin(\frac{x32ft/s^2}{v^2})}{2}$ since the arcsin is the inverse function of the sin.

Since we have x = 170 ft and v = 85 ft/s, we can substitute these values from the equation written, and we will have $\theta=\frac{Arcsin(\frac{(170ft)(32ft/s^2)}{(85ft/s)^2})}{2}$ , and from now on we have just to use a calculator, obtaining $\theta=\frac{Arcsin(0.75294117647)}{2}=\frac{48.84579804^\circ}{2}=24.4^\circ$

3 0

3 years ago

In ΔBCD, the measure of ∠D=90°, DC = 16, CB = 65, and BD = 63. What ratio represents the cosine of ∠B?

Alisiya [41]

Answer:

15:17

Step-by-step explanation:

Since the triangle has a right angle, we may find the length of the unknown side using the trigonometric notations SOH CAH TOA where

SOA stands for

Sin Ф = opposite side/hypotenuses side

Cosine Ф = adjacent side/hypotenuses side

Tangent Ф = opposite side/adjacent side

With respect to ∠B given that ∠D=90°,

BD is the adjacent side

CB is the hypotenuse side

and DC is the opposite side

Hence Sin B = 15/17

8 0

3 years ago

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