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Lesechka [4]
3 years ago
8

What are solutions to the equation 9x2-7x-4=0

Mathematics
1 answer:
11111nata11111 [884]3 years ago
3 0

Answer:

Step-by-step explanation:

x =(7-√193)/18=-0.383

x =(7+√193)/18= 1.161

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Given that 12 , 3 is on the graph of f(x) find the corresponding point for the function
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PLEASE HELP ME !<br> (2,7); 3x-y =5<br> show all steps !
Zigmanuir [339]

Answer:

i dont think you've got the right (x,y) pair....

Step-by-step explanation:

3x - y = 5

3(2) - 7 = 5

6 - 7 = 5

those are not the correct coordinates for the equation

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2 years ago
Sallly has 3 marbles. Every
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If Sally already has 3 marbles and she finds 5 everyday. That means you add 5 until you get to 58. So in this case 5 times 11 is 55 + 3 is 58. Answer: It will take 11 days at this rate for her to have 58 marbles.
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3 years ago
Sam is handing out advertisements for an upcoming event. He starts with a box of 5,000 advertisements and hands out 12 advertise
lawyer [7]

Answer:

n = 5,000 - 12t ​

Step-by-step explanation:

Sam is handing out advertisements for an upcoming event.

No of advertisements = 5000

No of advertisements per minute is 12.

We need to find the equation that best models the relationship between the amount of time t, Sam spends handing out advertisements and the number of advertisements, n, remaining.

5000 is fixed and there are 12 advertisements per minute. Let the equation is given by :

n = 5,000 - 12t ​

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7 0
3 years ago
A box contains 35 gems, of which 10 are real diamonds and 25 are fake diamonds. Gems are randomly taken out of the box, one at a
USPshnik [31]

Answer:

Probability = 0.504

Step-by-step explanation:

Given

Gems= 35

Real = 10

Fake = 25

Required

Determine the probability of selecting two fakes

The probability can be represented as thus: P(Fake\ and\ Fake)

Using the following probability formula, we have:

P(Fake\ and\ Fake) = P(Fake) * P(Fake)

Each probability is calculated by dividing number of fakes by total number of gems:

P(Fake\ and\ Fake) = \frac{25}{35} * \frac{25-1}{35-1}

The minus 1 (-1) represent the numbers of fake and total gems left after the first selection

P(Fake\ and\ Fake) = \frac{25}{35} * \frac{24}{34}

P(Fake\ and\ Fake) = \frac{5}{7} * \frac{12}{17}

P(Fake\ and\ Fake) = \frac{60}{119}

P(Fake\ and\ Fake) = 0.504

<em>Hence, the required probability is approximately 0.504</em>

7 0
3 years ago
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