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Liono4ka [1.6K]
3 years ago
8

Can someone please help me with these two questions?

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0

the first picture you have to use B X L X H ( base, length and height) and i got 1728 mm^3

for the second one, you have to use the formula L X H ( P+ Q/2) ( length times height times the product of the base width plus the top width divided by 2 and i got the answer of 196 m^3.

i hope this helps :)

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A

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Evgesh-ka [11]

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x=10/3 y=17/3

Step-by-step explanation:

Use substitution to solve your equation. Plug in y=2x-1 into y=1/2x+4. This makes (2x-1)=1/2x+4. Simplify this to get 3/2x-1=4. Simplify it again to get 3/2x=5. No one likes fractions so multiply both sides by 2 to get 3x=10. Simplify this and get x=10/3. Plus 10/3 into one of the equations. You can pick anyone but I picked y=2x-1. Because you know x=10/3, you put y=2(10/3)-1. Simplify this and get y=20/3-1. Convert 1 into a fraction and get y=20/3-3/3. Simplify this and get y=17/3.

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3 years ago
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Choose the equation of the horiontal line that passes though the point<br> 2,3
Rzqust [24]

The horizontal line has an equation: y = a, where a is any real number.

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How do I do number 5?
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H(t)=-16t^2+15t+12
(e)
maximum height is reached when h'(t)=-32t+15=0, or tm=15/32 seconds.
maximum height reached = h(tm)=h(15/32)=-16(15/32)^2+15(15/32)+12
=993/64 ft
=15.516 ft.
(f) when Greg reaches water, h(t)=0=-16t^2+15t+12
Solve for t using quadratic formula,
t=[-15+/- sqrt(15^2+4*12*16)]/(2*-16)
=-0.516s or 1.4535s.
Reject negative root so
Greg reaches water at t=1.4535 seconds.
3 0
3 years ago
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