<h2>7−n=16</h2>
<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>
Answer:
The answer to your question is:
x = 4
y = -1
z = -3
Step-by-step explanation:
3 x + 2 y + z = 7
5 x + 5 y + 4 z = 3
3 x + 2 y + 3 z = 1
![\left[\begin{array}{ccc}3&2&1\\5&5&4\\3&2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%262%261%5C%5C5%265%264%5C%5C3%262%263%5Cend%7Barray%7D%5Cright%5D)
= 45 + 10 + 24 - (30 + 24 + 15)
= 79 - 69
Δ = 10
![\left[\begin{array}{ccc}7&2&1\\3&5&4\\1&2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%262%261%5C%5C3%265%264%5C%5C1%262%263%5Cend%7Barray%7D%5Cright%5D)
= 105 + 6 + 8 - (18 + 56 + 5)
= 119 - 79
Δx = 40
![\left[\begin{array}{ccc}3&7&1\\5&3&4\\3&1&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%267%261%5C%5C5%263%264%5C%5C3%261%263%5Cend%7Barray%7D%5Cright%5D)
= 27 + 5 + 84 - ( 105 + 12 + 9)
= 116 - 126
Δy = -10
![\left[\begin{array}{ccc}3&2&7\\5&5&3\\3&2&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%262%267%5C%5C5%265%263%5C%5C3%262%261%5Cend%7Barray%7D%5Cright%5D)
= 15 + 70 + 18 - (10 + 18 + 105)
= 103 - 133
= -30
Δz = -30
x = Δx /Δ = 40/10 = 4
y = Δy/Δ = -10/10 = -1
z = Δz/Δ = -30/10 = -3
Answer:
1.641× 10^-3 pounds/ cubic inch
Step-by-step explanation:
Density= mass / volume
Mass of the material= 9 kilograms
Volume= 7 cubic feet
Density= 9/7= 1.286 kg/ ft^3
Density= 1.286 kg/ ft^3
To Convert to pounds per inch
1 kg/ ft^3 = 0.00128 pound / cubic inch
1.286 kg/ ft^3 = X pounds/ cubic inch
X=( 1.286 × 0.00128)
= 0.0016407087 pounds/ cubic inch
= 1.641× 10^-3 pounds/ cubic inch
Hence,this density in pounds per inch is 1.641× 10^-3 pounds/ cubic inch
Answer: The player is catching the ball at (4,25), therefore the second option is correct.
Explanation:
It the given graph x-axis represents the time (in seconds) after throw and y-axis represents the distance from goal (in yards).
In the graph violet and orange lines represents the distance of player and ball respectively, from the goal at different point of time.
The player will catch the ball when the distance of player and ball from the goal is same on the single point of time.
The point of time where distance of player and ball from the goal is same, is the point of intersection of both lines.
From the graph it is clearly noticed that both lines violet and orange insects at point (4,26), therefore player is catching the ball at (4,25), therefore the second option is correct.
