I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
Answer:
5x²
Step-by-step explanation:
because polynomials are the expressions where many terms are involved
Answer: y + 4 = -3(x+1)
Step-by-step explanation:
We need to rewrite in form of y=mx+b.
3x+y=5
y = -3x + 5
The slope is -3.
In addition, the slope of two parallel line would be equal, the slope of the line would be -3.
y- y1 = m(x- x1)
y- (-4) = -3(x - -1)
y + 4 = -3(x+1)
|DF| = |DE| + |EF| |DF| = 9x -36 |DE| = 47 |EF| = 3x+10 Substitute: 9x - 39 = 47 + 3x + 10 9x - 39 = 3x + 57 |+39 9x = 3x + 96 |-3x 6x = 96 |:6 x = 16 Put the value of x to the equation |EF| = 3x + 10 |EF| = (3)(16) + 10 = 48 + 10 = 58 Answer: |EF| = 58
Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/4046336-if-df-9x-39-find-ef.html
