Answer:
If all you care about is whether you roll 2 or not, you get a Binomial distribution with an individual success probability 1/6. The probability of rolling 2 at least two times, is the same as the probability of not rolling 2 at zero or one time.
the answer is, 1 - bin(k=0, n=4, r=1/6) - bin(k=1, n=4, r=1/6). This evaluates to about 13%, just like your result (you just computed all three outcomes satisfying the proposition rather than the two that didn’t).
Step-by-step explanation:
The answer to your query is 19.2
Equation 1 is 
,
Equation 2 is [/tex] 3x-2y = -1 [/tex]
for first equation LCD= 3 *5 = 15 , So we multiply whole equation by 15
Now multiply second equation by -3 , to make the coefficient of y equal and opposite , so that we can apply the elimination method
Add both the equations
Divide both sides by 11
Plug in any one of the equation we get
3(3) -2y = -1
9 - 2y = -1
subtract 9 from both sides
-2y = -10
divide both sides by -2
y=5
So the solution is x= 3 , y= 5
Which means
a. The system is consistent and independent. TRUE
Answer: x° = 77°
Step-by-step explanation:
x + 103 = 180
x = 180 - 103
x = 77°
also by properties:
x° = 42° + 35° = 77°
Answer:
Probability of choosing green and yellow treat is higher than Probability of choosing an orange and yellow treat by 0.08
Step-by-step explanation:
Given -
Green and yellow gummy treats = 20
Red and yellow gummy treats = 14
Orange and yellow gummy treats = 16
Total gummy treat = 20+14+16 = 50
Probability of choosing green and yellow treat = 20/50 = 0.4
Probability of choosing an orange and yellow treat = 16/50 = 0.32
Probability of choosing green and yellow treat is higher than Probability of choosing an orange and yellow treat by 0.08
