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sergiy2304 [10]
3 years ago
13

Hi, anyone can help with this Thanks!!

Mathematics
1 answer:
Airida [17]3 years ago
8 0

Answer:

sas

Step-by-step explanation:

side angle side,

since cf and cb are the same measurement (represented by the line in the line), the angles are the same also (curves), they are congurent

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Kevin entered a pie eating contest he ate 4 pies in 132 seconds what is Kevin going unit rate
8090 [49]
One pie every 33 seconds

6 0
3 years ago
Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and
Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling:

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.85}{\sqrt{35}} = 0.1437

P(sample average sediment density is at most 3.00)

P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)

Calculation the value from standard normal z table, we have,  

P(x \leq 3.00) = 0.918

0.918 is the probability that the sample average sediment density is at most 3.00

4 0
3 years ago
Help please my teacher isn't the greatest.
Schach [20]

Answer:

x = 9.5

Step-by-step explanation:

We see that the entire length of DF is equal to 34. That means segment DE and segment EF must combine to equal 34:

3x - 6 + x + 2 = 34

4x - 6 + 2 = 34

4x - 4 = 34

4x = 38

x = 9.5

6 0
3 years ago
Read 2 more answers
A stadium has a a central rectangular area 125m long by 80m wide.there are two semi circular ends.a running track goes all the w
Fudgin [204]

a)The total inside length of the curved ends of the track will be 25.13 meters

b)The total distance around the inside of the track will be 275.13 meters

c)The area inside the track is 10050 square meters.

<h3>What is an area?</h3>

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the circle in a two-dimensional plane is called the area of the circle.

Given that:-

A stadium has a central rectangular area 125m long by 80m wide. there are two semi-circular ends. a running track goes all the way around.

a) what is the total inside length of the curved ends of the track?

The length of the curved track means it is a perimeter of the circle so the radius of the semicircle will be 4 meters.

So the length will be = π r + πr = 2 πr

                                  = 2 x π x 4 = 25.13

b) what is the total distance around the inside of the track?

The total distance of the track will be the sum of the length of the two semicircles and the longer side of the rectangle.

Total length = 125 + 125 + 25.13

                     = 275.13 meters

c) what is the area inside of the track?

The area will be equal to the area of the two semicircular tracks and the rectangular track.

Total Area = Area of semicircle + Area of semicircle + Area of rectangle

                  = ( π/2 ) r² + (π/2) r² + ( L x W )

                  =  π  r² + (  L x W)

                  = π ( 4 )² + ( 125 x 8 )

                  = 10050.26 square meters.

Therefore the total inside length of the curved ends of the track will be 25.13 meters. The total distance around the inside of the track will be 275.13 meters. The area inside the track is 10050 square meters.

To know more about an area follow

brainly.com/question/25292087

#SPJ1

3 0
2 years ago
What is the exact area of a circle with a radius of 11 feet?
Phoenix [80]
11 feet 121 PI square feet
6 feet 36 PI square feet
6 0
3 years ago
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