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Svetradugi [14.3K]
3 years ago
6

Solve the equation and find value of 'x' in 2x=(360/4)

Mathematics
1 answer:
uranmaximum [27]3 years ago
8 0
2x = 360/4
x = 90 / 2
x = 45

Hope this is the answer you are looking for! 
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Help me find the answer
RUDIKE [14]

X= 14

2(X+4) = 2x+8
3x-6 = 2x+8
-6=2x-3x+8
-14 = -1x
X=14
6 0
3 years ago
Read 2 more answers
You wish to find a 95% confidence interval for the mean number of times men change channels with a remote control during a comme
gogolik [260]
For margin of error to be a maximum of 3:
3 = z*(SD / sqrt(n)), where z is the z-score, SD is the standard deviation and n is the sample size.
z = 1.96 for a 95% confidence interval, and we are given SD = 15.
3 = 1.96*15/sqrt(n)
sqrt(n) = 9.8
n = 96.04 ~ 96 commercials.

4 0
3 years ago
A line is represented by the equation y=x-7. What is the y-intercept of the line?
DedPeter [7]

Answer: -7

In the slope-intercept format y = mx+b, b is always the y-intercept. If it is with a positive sign, the y-intercept is positive and if it is negative then the y-intercept is negative.

3 0
3 years ago
Read 2 more answers
a school musical soild 353 tickets. $5 for adults and $3.50 for students. the school made $1500 how many adult tickets were sold
IrinaVladis [17]

Answer:

177 Students

176 Adults

Step-by-step explanation:

Adult - (A) $5

Student - (S) $3.50

Equation 1: A+S = 353 tickets

Equation 2: 5A + 3.50S = $1500

Sub equation 1 into 2:

5A + 3.50(353 - A) = 1500

Multiply: 5A + 1235.50 -3.50A =1500

Subtract 1235.50 and -3.50A from both sides: 1.50A = 264.50 and then divide:

264.50/1.50 = 176 Adults

Sub into equation 1:

176 +S = 353

Solve: 353 - 176 = 177 Students

Check: 5(176) + 3.50(177) = $1500

1499.5 rounded = 1500 = 1500 ✔

I hope this helped!

3 0
3 years ago
Pls help need it ASAP
vitfil [10]

Answer:

3x-2y=17........(1)

x=4y-1

substituting value of x in equation 1

3(4y-1)-2y=17

12y-3-2y=17

10y=17+3

y=20/10=2

again

substituting value of y in equation 1

3x-2×2=17

3x=17+4

x=21/3=7

:.x=7,y=2

3 0
3 years ago
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