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SIZIF [17.4K]
3 years ago
11

Given: Sine (A) = four-fifths, StartFraction pi Over 2 EndFraction < A < Pi and Sine (B) = StartFraction negative 2 StartR

oot 5 EndRoot Over 5 EndFraction, pi, Pi < B < StartFraction 3 pi Over 2 EndFraction
What is the value of cos(A – B)?

Negative StartFraction 2 StartRoot 5 EndRoot Over 25 EndFraction
Negative StartFraction StartRoot 5 EndRoot Over 5 EndFraction
StartFraction 2 StartRoot 5 EndRoot Over 5 EndFraction
StartFraction 11 StartRoot 5 EndRoot Over 25 EndFraction

Mathematics
2 answers:
ELEN [110]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Did test(edge 2020)

Marianna [84]3 years ago
4 0

Answer:

d

Step-by-step explanation:

edge 2020

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Section B: Multiples and factors 1. Why is the number 17 classified as a prime number? ​
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17 is a prime number because it’s only divisible by 1 and it’s self, so it only has 2 factors.
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Solve for y: - √(y) = -5
Serggg [28]
-sqrt(y) = -5

Multiply each side by (-) negative sign: sqrt(y) = 5

Square each side: y = 25

Answer: (C) 25

 


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Need help with problem 5, Thank you!<br><br><br> Sorry for the glare
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Answer:

x = 57

Step-by-step explanation:

A triangles degrees add up to 180

67 + 56 = 123

180 - 123 = 57

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8

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1. 3b - 2 (1 - b) / a - 2

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2 years ago
Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

6 0
2 years ago
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