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antoniya [11.8K]
4 years ago
12

M+4=17solve each equation mentally​

Mathematics
1 answer:
SCORPION-xisa [38]4 years ago
4 0
-4 from each side
m=13
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GIVING BRAINLY
Virty [35]

Step-by-step explanation:

The only difference between ultimate Frisbee and basketball is the equipment; instead of using a ball, a disc is used; however, either way it is the same concept. That way, if young athletes play this game in your next practice, they may also develop an interest in ultimate Frisbee and it may be something they explore later on in their athletic careers.

The premise of this game is to pass the ball into the opposing team’s endzone and score the most points. The offensive players are not allowed to dribble the ball or allow the ball to touch the ground, if that does happen it results in a change of possession and turnover. I think this game is a fun way to teach the young athletes how to pass the ball around to their teammates and how to move to open spaces on the court. By playing this game in your practice, you are working on basketball-specific skills, but also teaching young children a sport they may have never heard of or played before; therefore, creating exposure to new activities.

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3 years ago
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What happened to the tutor option :(
ElenaW [278]

Answer: wym

Step-by-step explanation:

6 0
3 years ago
What is 19,761 divisible by​
olga55 [171]
1, 3, 7, 21, 941, 2823, 6587, 19761
6 0
4 years ago
A box contains eighteen $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill. You blindly reach into the
zubka84 [21]

Answer:  $7.70

Step-by-step explanation:

Given : A box contains eighteen $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill.

Total bills = 18+10+8+3+1=40

We know that probability of any event =\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

i.e. the probability of getting $1 bills =P(E_1)=\dfrac{18}{40}=0.45

Probability of getting $10 bills =P(E_2)=\dfrac{10}{40}=0.25

Probability of getting $5 bills =P(E_3)=\dfrac{8}{40}=0.2

Probability of getting $20 bills =P(E_4)=\dfrac{3}{40}=0.075

Probability of getting $100 bills =P(E_5)=\dfrac{1}{40}=0.025

\text{Expected value =}1\times P(E_1)+5\times P(E_2)+10\times P(E_3)+20\times P(E_4)+100\times P(E_5)\\\\=1\times 0.45+5\times 0.25+10\times0.2+20\times 0.075+100\times 0.025\\\\=7.7

Hence, the expected value of your draw= $7.70

5 0
4 years ago
In the figure below, what is the length of<br> MN?
Diano4ka-milaya [45]
There is no figure below.
6 0
3 years ago
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