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Crank
4 years ago
6

The perimeter of a rectangle pool is 160 yards. if the length is 10 yards less than twice the width, find the length and the wid

th
Mathematics
1 answer:
uranmaximum [27]4 years ago
3 0

Answer: lenght is 50yrds, width is 30yrds

Step-by-step explanation:

Perimeter of a pool = 2( lenght x breadth)

Perimeter = 160yrds

If the lenght is 10yrds less than twice the width then,

lenght = 2w - 10,

Where w is the width

Then from p = 2(L + w)

160 = 2( 2w - 10 + w)

160 = 2(3w - 10)

160 = 6w - 20

160 + 20 = 6w = 180

width w = 180/6 = 30yrds

From p = 2(L + w)

160 = 2(L + 30)

160 = 2L + 60

160 - 60 = 2L = 100

L = 100/2 = 50yrds

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What is the measure of the base of the rectangle if the area of the triangle is 32ft^2?
olganol [36]

Answer:

Ok so you need the basic which is 334

Step-by-step explanation:

ok 32ftx2= 64 i hope that helps you

3 0
2 years ago
The diagram shows a right angled triangle use pythagoras theorem to work out length of side ac
Strike441 [17]

Answer:

Step-by-step explanation:

Using Pythagoras theorem,

AC^2 = AB^2 + BC^2

AC^2 = 4^2 + 15^2

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4 0
4 years ago
Three ice skating rinks were open at the same time on Saturday. Sparkle Skate had
zmey [24]

Answer:

  • Sparkle: 104
  • Southern: 208
  • Scenic: 416

Step-by-step explanation:

The ratios of people at each rink were ...

  Sparkle : Southern : Scenic = 1 : 2 : 4

The total number of ratio units is 1+2+4 = 7, so each one must stand for 728/7 = 104 skaters. Then the ratios of the numbers of skaters were ...

   Sparkle : Southern : Scenic = 104 : 208 : 416 . . . multiply ratio units by 104

People skating were ...

  • Sparkle: 104
  • Southern: 208
  • Scenic: 416
4 0
2 years ago
Ramesh buys a pen for rs 20 and sells it at 20% profit for what price should he buy it so that he can make 25% profit by selling
laiz [17]

CP of pen = ₹20

Profit % = 20%

Profit % = profit × 100 / CP

20 = profit × 100 / 20

20 × 20 / 100 = profit

Profit = ₹4

Profit = SP - CP

4 = SP - 20

SP = ₹24

Let new CP be ₹x

Profit % = 25%

SP = ₹24

Profit % = SP - CP

25x / 100 = 24 - x

24x / 100 + x = 24

125x / 100 = 24

5x / 4 = 24

x = 24 × 4 / 5

x = ₹ 19.20

6 0
3 years ago
Can anyone help me with these two problems?
Veseljchak [2.6K]

Show

\dfrac{\sin ^2 x + \sin x \cos x}{\cos x - 2 \cos^3 x} = \dfrac{\tan x}{\sin x - \cos x}

I don't like this computer aided instruction holding my hand.  I'll ignore that at first so I can compare my solution to the one being taught.

We can see how a tan factors out; let's see what's left.

\dfrac{\sin ^2 x + \sin x \cos x}{\cos x - 2 \cos^3 x}

=\dfrac{\sin x}{\cos x} \cdot \dfrac{ \sin x + \cos x}{1 - 2 \cos^2 x}

We need to factor out a sin x + cos x in the denominator so let's change one of the squared cosines to squared sine.

= \tan x \dfrac{ \sin x + \cos x}{1 - \cos^2 x - (1 - \sin ^2 x)}

= \tan x \dfrac{ \sin x + \cos x}{\sin^2 x - \cos^2 x}

= \tan x \dfrac{ \sin x + \cos x}{(\sin x + \cos x)(\sin x - \cos x)}

=\dfrac{\tan x}{\sin x - \cos x} \quad\checkmark

OK, now I can look at what they did.

First step ok, the box is 2 cos^2 x

Second step they changed the 1, box same as before: 2 cos^2 x

Third box matches our proof,  cos^2 x

Fourth box our last box didn't change:  cos^2 x

Fifth box: sin x + cos x

6 0
3 years ago
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